<span>The surface of the triangle count formula
A = b*h*1/2
A - area
b - base
c - height
</span><span>The first triangle
A</span>₁ = b₁*h = 6in * 8in *1/2= 24in²
<span>The second triangle
</span>A₂ b₂*h = 10in * 8in*1/2 = 40in²
The total area of the two triangles is 24in² + 40in² = 64 square inches
Answer:
![Wire\ length = 36\ in](https://tex.z-dn.net/?f=Wire%5C%20length%20%3D%2036%5C%20in)
Step-by-step explanation:
Given
![Wire\ length = 1\ yard](https://tex.z-dn.net/?f=Wire%5C%20length%20%3D%201%5C%20yard)
Required
The wire length in inches
<em>The question requires that we convert from yard to inches.</em>
To do this, we simply convert yard to inches by multiplying the wire length by 36.
So, we have:
![Wire\ length = 1\ in * 36](https://tex.z-dn.net/?f=Wire%5C%20length%20%3D%201%5C%20in%20%2A%2036)
![Wire\ length = 36\ in](https://tex.z-dn.net/?f=Wire%5C%20length%20%3D%2036%5C%20in)
This is a problem for which you will have to use the Pythagorean theorem.
The Pythagorean theorem states that:
x^2 + y^2 = h^2
where x and y are the legs, and h is the hypotenuse.
Let h = 20 ft, and x = 16
16^2 + y^2 = 20^2
Now, solve for y.
256 + y^2 = 400.
256 - 256 + y^2 = 400 - 256
y^2 = 144
y = 12
The length of the other leg is 12 feet.
If its going by $11 for 2 hours then he babysat ?
ok so $11= 2 hours
11 x 3= 33 half of eleven is 5.5
so 33+ 5.5 = $38.50 so I believe the answer is 6 hours and 30 min but I'm not 100 percent positive
So to start off, we would make 1/3 2/6 so that the bottom number is the same. 2/6 can go in to 5/6 twice so the answer is two bags.