The answer is d
This is the answer because you multiply 52 by 18% and then add the answer to 52 and will getD
1) 32% students chose red, yellow, & orange.
Find the total number of students that gave their favorite color.
6 + 4 + 8 + 7 + 9 + 3 + 4 + 9 = 50 students
Find the students that chose red, yellow, and orange.
9 + 4 + 3 = 16
16 out of 50 students chose red, yellow, & orange as their favorite color.
16/50 = 32/100, which is 32%.
2) No, 2/25 students chose pink, which is less than 1/10.
Find the number of students that chose pink -- 4 students. 4 out of 50 students. 4/50 reduced is 2/25.
2/25 is 0.08.
1/10 is 0.10.
So, less than 1/10 of the students chose pink as their favorite color.
3) 18% students chose blue as their favorite color.
Find how many students chose blue -- 9 students.
9 students out of 50 students, 9/50. Multiply both sides by 2 to get 18/100.
18/100 is 18 percent.
4) 21/50 students chose green, black, & purple.
Find how many students chose green, black, and purple.
7 + 8 + 6 = 21
21 out of 50 students, 21/50.
<h3>Explanation:</h3>
(16^4 -2^13 -4^5) mod 11 = ((2^4)^4 -2^13 -(2^2)^5) mod 11
= (2^16 -2^13 -2^10) mod 11
= (2^10 mod 11)·((2^6 -2^3 -1) mod 11)
= (1024 mod 11)·(55 mod 11)
= 1 · 0 = 0
When the sum shown above is divided by 11, its remainder is zero. Hence the sum is divisible by 11.
<span>66.9999953 is the answer.</span>
Answer:
(89.2 - 92.4) ± 1.666*√(3.1²/38 + 3.8²/37)
Step-by-step explanation:
Very clear deck :
n1 = 38
x1 = 89.2
s1 = 3.1
Sure seal
n2 = 37
x2 = 92.4
s2 = 3.8
Confidence interval for difference in sample means :
(X1 - X2) ± margin of error
(X1 - X2) ± Tcritical * sqrt(s1²/n1 + s2²/n2))
Using the degree of freedom calculator ; df = 70
Margin of Error : Tcritical * sqrt(s1²/n1 + s2²/n2))
Tcritical at 90% confidence interval, df = 70 = 1.688
Margin of Error = 1.666 * sqrt(3.1²/38 + 3.8²/37)
Confidence interval :
(89.2 - 92.4) ± 1.666*√(3.1²/38 + 3.8²/37)