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Harman [31]
3 years ago
9

What is 329 to the nearest 100

Mathematics
2 answers:
yuradex [85]3 years ago
5 0
Here we will tell you what 329 is rounded to the nearest hundred and also show you what rules we used to get to the answer. First, 329 rounded to the nearest hundred is:

300

<span>Remember, we did not necessarily round up or down, but to the hundred that is nearest to 329.</span>
Salsk061 [2.6K]3 years ago
3 0
329 you have to round so it would be 300
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What's the quotient of 13 divided by 1690?
Mnenie [13.5K]
1690 divided by 13 equals 130

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3 years ago
Sam has $65 to spend on clothes. He wants to buy a pair of jeans for $29 and spend the rest on t-shirts. Each t-shirt costs $9.
Alekssandra [29.7K]

money >= jeans + tshirts

65 >= 29 + 9* number of shirts

subtract 29 from each side

36> =9 *number of shirts

divide by 9 on each side

4 > =number of shirts

He can buy 4 or less shirts

Choice A


5 0
3 years ago
Read 2 more answers
Cw 11.1 backside v. V.
nika2105 [10]

Answers:

10.  28.3 cm²

11. 7.3 cm²

12. P: 32 yds, A: 76.8 sq yds

13. P: 64 units, A: 220.8 units

14.  50.3 cm²

15. 132.7 cm²

16. 9.7 in

17. 5.9 cm

18.  324.08 sq inches.

19. 39 cm²

20. 36.6 cm²

Step-by-step explanation:

10. Find the area of the shaded region.

It's a circle, let's first calculate its area, with the formula A = π * r²

A = π  * 6² = 36 π  = 113.1 cm²

The shaded area has a 90 degrees angle... so it's 1/4 of the whole circle.

The area of the shaded area of this circle is then: 113.1 * 1/4 = 28.275 cm²

Rounded to the tenths, that's of course 28.3 cm²

11. Find the area of the shaded region.

Again, let's first find the area of the complete circle, with A =  π * r²

A =  π * 4² = 16π  = 50.27 cm²

Now, let's find the angle for the shaded area.

A circle has 360 degrees, and we know the angles of 2 segments... so we can easily find the missing angle:

360 - 203 - 105 = 52

The shaded area has an arc of 52 degrees, so we multiply the area of the full circle by 52/360 to get the area of that shaded area:

(50.27 * 52) / 360 = 7.26 cm², rounded to the tenths: 7.3 cm²

12. Find perimeter AND area of this regular polygon.

The figure is a regular octagon (8 sides).

To calculate its perimeter, it's simply 8 times one side, so: 8 * 4 yd = 32 yds

For the area, you can view an octagon as 8 triangles joined together.  In this case, we have a base of 4 yds and a height of 4.8 yds, so the area of each triangle is: (4 * 4.8) /2 = 9.6, the total area of the octagon is then 8 * 9.6 = 76.8 yds

13. Find perimeter AND area of this regular polygon.

The figure is a regular octagon (8 sides).

To calculate its perimeter, it's simply 8 times one side, so: 8 * 8 = 64 units

For the area, you can view an octagon as 8 triangles joined together.  In this case, we have a base of 4 yds and a height of 4.8 yds, so the area of each triangle is: (8 * 6.9) /2 = 27.6, the total area of the octagon is then 8 * 27.6 = 220.8 units

14. Find the area of a circle of <u>radius</u> = 4 cm

We have a circle with a radius of 4 cm, we need to find its area.

The area of a circle is obtained by the formula: A = π * r²

We already have the value of r, so we will input it in the formula:

So, we'll have A = π * 4² = 16 * π = 50.27 cm²

Rounded to the tenths: 50.3 cm²

15. Find the area of a circle of <u>diameter</u> 13 cm

We have a circle with a diameter of 13 cm, we need to find its area.  To use the formula for the area, we need the radius, not the diameter.  Since the diameter is 13 cm, the radius is 6.5

The area of a circle is obtained by the formula: A = π * r²

So, we'll have A = π * 6.5² = 42.25 * π = 132.73 cm²

Rounded to the tenths: 132.7 cm²

16. Find the diameter of a circle with an area of 75 in².

We just used the area formula for a circle, based on the radius.  We'll process it in reverse from the area to get the radius... which will give us the diameter, so r² = A / π

We then have:  r² = 75 / π = 23.87

So, r = 4.88 (square root of 23.87), which we double to get the diameter: 9.76 in, rounded to 9.7 in.

17. Find the radius of a circle with an area of 108 cm².

We just used the area formula for a circle, based on the radius.  We'll process it in reverse from the area to get the radius, so r² = A / π

If we input the area given in the question into the formula, we have:  r² = 108 / π = 34.38 cm

So, r = 5.86 (square root of 34.38), rounded to 5.9 cm.

18. Find the area

We have here a half-circle with a triangle.

We just used the formula for the area of a circle, and we know the radius of that half-circle: 8 inches.

A = π * 8² = 64 * π = 201.06 sq inches, for the whole circle.

But we only have half of it, so 201.06 / 2 = 100.08 sq inches.

Now the triangle.  To calculate the area of a triangle, you multiply its base by its height, then you divide by 2, so:

A = 16 x 28 = 224 sq inches.

Which we add to the half-circle area (100.08 sq inches) to get 324.08 sq inches. So 324.1 sq inches once rounded to the tenths.

19. Find the area

We have a triangle on top of a rectangle.

Area of a triangle: (base * height) / 2.

Area of a rectangle: base * height

So, for the triangle: A = (6 * 3) / 2 = 9 cm²

And for the rectangle: A = 6 * 5 = 30 cm²

Total: 9 + 30 = 39 cm²

20. Find the area

We have a rectangle and a half circle.  The radius of the half-circle is: 2 cm (half of the height of the rectangle).

Area of the rectangle: base * height, so 6 * 4 = 24 cm²

Area of the circle:  π * r² = π * 2² = 4π = 12.56 cm²

Total for the figure: 24 + 12.56 = 36.56, or 36.6 cm² once rounded.

3 0
3 years ago
Garth estimated the height of the door ti his classroom in meters. what is a reasonable estimate?
chubhunter [2.5K]
2 because 3 meters is labor 6 feet and 2 is above 5'9'' so it's kinda understandable
7 0
3 years ago
When using base-10 blocks to divide 452 by 2, how many hundreds flats will be in each equal group? hundreds flats Divide 452 by
daser333 [38]
<h3>Given</h3>

4 hundreds flats; 5 tens rods; 2 ones cubes

<h3>Find</h3>

The number of hundreds flats in each of 2 equal piles

<h3>Solution</h3>

When 4 flats are divided into two equal groups, each group will have ...

... 2 flats

_____

You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.

— — — — —

You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.

8 0
3 years ago
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