1.7 is the answer to the question
Answer is: a= -4
STEP
1
:
1
Simplify —————
a + 3
Equation at the end of step
1
:
a 3 1
(————————+—————)-——— = 0
((a2)-9) (a-3) a+3
STEP
2
:
3
Simplify —————
a - 3
Equation at the end of step
2
:
a 3 1
(————————+———)-——— = 0
((a2)-9) a-3 a+3
STEP
3
:
a
Simplify ——————
a2 - 9
Equation at the end of step
3
:
a 3 1
(————————————————— + —————) - ————— = 0
(a + 3) • (a - 3) a - 3 a + 3
Equation at the end of step
4
:
(4a + 9) 1
————————————————— - ————— = 0
(a + 3) • (a - 3) a + 3
Pull out like factors :
3a + 12 = 3 • (a + 4)
Equation at the end of step
6
:
3 • (a + 4)
————————————————— = 0
(a + 3) • (a - 3)
3•(a+4)
——————————— • (a+3)•(a-3) = 0 • (a+3)•(a-3)
(a+3)•(a-3)
a+4 = 0
Subtract 4 from both sides of the equation :
a = -4
#1 7.1 years old
#2 7.8 years old
#3 87.4
#4 74
#5 7.4
Set up an equation:
3x - x = 28
Simplify:
2x = 28
Divide both sides by 2
X = 14
3(14) = 42
The numbers are 42 and 14
If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
