Answer:
Step-by-step explanation:
Part A:
To find the total length of sides 1, 2, and 3 of the quadrilateral add all three sides together.
Side 1: 3y2 + 2y − 6
Side 2: 3y − 7 + 4y2
Side 3: −8 + 5y2 + 4y
3y^2+2y-6+3y-7+4y^2-8+5y^2+4y
Combine the like terms:
12y^2+9y-21
Part B:
To find the length of the fourth side of the quadrilateral we have the total perimeter and the sum of three of the sides, so you just need that fourth side value. Let the fourth side be d.
P= 4y3 + 18y2 + 16y − 26.
Sides = 12y^2+9y-21
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d
Separate d from rest of the terms.
d = -12y^2-10y+21+4y^3+18y^2+16y-26
d = 4y^3+6y^2+6y-5
Part C:
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y^2, y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms....
