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gogolik [260]
4 years ago
7

On a piece of paper, use a protractor to construct △ABC with m∠A=30° , m∠B=60° , and m∠C=90° .

Mathematics
2 answers:
laiz [17]3 years ago
8 0

Answer:

The answer is BC < AC and BC < AB

So D and C are the answers

siniylev [52]3 years ago
4 0
The answer is BC < AC and BC < AB

I just did the test this right right.
hope I helped.

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Consider the tangent line to the curve y = 6 sin(x) at the point (π/6, 3). (a) Find a unit vector that is parallel to the tangen
mojhsa [17]

Answer:

y=\frac{\pi }{6}+5.196(x-3)

Step-by-step explanation:

We have given the equation y = 6 sin (x)

On differentiating both side \frac{dy}{dx}=m=6cosx

As it passes through the point (\frac{\pi }{6},3)

So \frac{dy}{dx}=6cos\frac{\pi }{6}=5.196

Now the unit vector is parallel to the tangent so m will be 5.196

This passes through the point (\frac{\pi }{6},3)

So unit vector will be y-\frac{\pi }{6}=5.196(x-3)

y=\frac{\pi }{6}+5.196(x-3)

5 0
3 years ago
Write with fractional exponents. 6^5 square root x^2 y​
sertanlavr [38]

Answer:

6xy^2/5 what im assuming is right

Step-by-step explanation:

4 0
2 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
telo118 [61]

Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









4 0
3 years ago
What is the value of pi to 10 decimal places
I am Lyosha [343]

Answer:

3. 415926535

Step-by-step explanation:

6 0
3 years ago
Help!!!!!!!Plz!!!!!!!
Hoochie [10]

Answer:

I'm so confused

Step-by-step explanation:

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3 years ago
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