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3 years ago

What is 2x-5y+15=0 written in slope-intercept form

2 answers:

8 0

slope intercept form is " y = mx + b ". 2x - 5y + 15 = 0 we have to get -5y on one side, so we will add 5y to both sides 2x + 15 = 5y now we have to divide by 5 to get y by itself (2x + 15)/5 = y 2/5x + 3 = y which equals y = 2/5x + 3

Nadya [2.5K]3 years ago

6 0

The answer is y=2/5x+3

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What is 7(3-k)=-3k+4 solved?

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2 years ago

Charlotte biked 4.8 × 104 meters. Mary biked 1.2 × 103 meters. How many times farther did Charlotte bike than Mary?

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3 years ago

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S=4LW+2WH;S+=136,L6,W=4 WHAT IS H

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H=5

Step-by-step explanation:

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3 years ago

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a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-

Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

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3 years ago

Find the LCM of n^3 t^2 and nt^4. A) n 4t^6 B) n 3t^6 C) n 3t^4 D) nt^2

patriot [66]

Answer:

The correct option is C.

Step-by-step explanation:

The least common multiple (LCM) of any two numbers is the smallest number that they both divide evenly into.

The given terms are $n^3t^2$ and $nt^4$ .

The factored form of each term is

$n^3t^2=n\times n\times n\times t\times t$

$nt^4=n\times t\times t\times t\times t$

To find the LCM of given numbers, multiply all factors of both terms and common factors of both terms are multiplied once.

$LCM(n^3t^2,nt^4)=n\times n\times n\times t\times t\times t\times t$

$LCM(n^3t^2,nt^4)=n^3t^4$

The LCM of given terms is $n^3t^4$ . Therefore the correct option is C.

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3 years ago

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