The answer is -a + b = 0
If she wants to solve <span>a system of linear equations by elimination and if one equation is unknown, one of the solutions in the unknown equation must be negative:
Known equation: a + b = 4
Unknown equation: -a + b = ?
We know that a = 2 and be = 2, thus:
</span>Unknown equation: -2 + 2 = 0
The general form of the equation is -a + b = 0
Let's check it out:
Known equation: a + b = 4
Unknown equation: -a + b = 0
________________________
Add them up: 2b = 4
b = 4/2 = 2
a + b = 4
a = 4 - b
a = 4 - 2
a = 2
So, the second equation is correct.
The angle between the two tangents drawn from an external point to a circle and the angle subtended by the line segment joining the points of the contact at the Centre are supplymentary,
So,
15.) let the unknown angle be x
=》x + 55° = 180°
=》x = 180° - 55°
=》
16. let the unknown angle be n
=》n + 80° = 180°
=》n = 180° - 80°
=》
Plot the sets of (x,y)
begin connecting the points until it says stop
when it says stop you will not connect the last point you graphed to the new point
so just plot the (x,y) connect the points and when it says stop you will start a connecting another set of points
We can also think of this problem as f(x) + g(x). Therefore, all we need to do is add the two functions together.
x + 4 + 3x^2 - 8 || Write it out!
3x^2 + x + 4 - 8 || Rearrange in order of decreasing exponents. No need to combine and rearrange all at once!
3x^2 + x - 4 || Combine like terms!
Hope this helps!! :)
Answer:
the info I read for the6th time indicates that its possible that angle 3 could be congruent to angle 5 or that angle 2 could congruent to angle 6 I'm honestly not sure just helping to brainstorm
Step-by-step explanation: