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Zarrin [17]
3 years ago
10

Zina solves a system of linear equations by elimination and finds a solution of (2, 2). One of the equations is a + b = 4. What

is the other equation?
Mathematics
2 answers:
kiruha [24]3 years ago
5 0
The answer is -a + b = 0

If she wants to solve <span>a system of linear equations by elimination and if one equation is unknown, one of the solutions in the unknown equation must be negative:
Known equation:       a + b = 4
Unknown equation: -a + b = ?

We know that a = 2 and be = 2, thus: 
</span>Unknown equation: -2 + 2 = 0
The general form of the equation is -a + b = 0

Let's check it out:
Known equation:       a + b = 4
Unknown equation: -a + b = 0
________________________
Add them up:            2b = 4
                                   b = 4/2 = 2

a + b = 4
a = 4 - b
a = 4 - 2
a = 2

So, the second equation is correct.
lana66690 [7]3 years ago
5 0

a+3b=8

Step-by-step explanation:

Option D

If you plot it on a graph the solution is 2, 2

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hmmm

so, how to turn our 5 to 15? well, 3*5, thus

\bf 3(x^3+2x^2+4x+8)=f(x)\implies 3(5)=f(-1)\implies 15=f(-1)

usually, when we get the roots, or zeros, if any common factor that is a constant is about, they get in a division with 0 and get tossed, and aren't part of the roots, thus, we can simply add one, in this case, the common factor of 3, to make the 5 turn to 15
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DiKsa [7]
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3 years ago
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