Question

4 algebra 1 questions if you know the answers please try to get me to understand

Answer 1

Distribute each term in one parenthesis to the other terms in the other parenthesis.

(x - 2) (2x + 3)

First, distribute x. When distributing, multiply

x(2x) = 2x²

x(3) = 3x

Next, distribute the other term, -2. Remember to change the signs.

-2(2x) = -4x

-2(3) = -6

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2x² + 3x - 4x - 6

Combine like terms

3x - 4x = -x

2x² - x - 6

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2x² - x - 6 is your answer

hope this helps

Answer 2

In order to distribute be sure to use the F.O.I.L method! Here's my work to help:

FOIL = first, outer, inner, last

1. (x-2)(2x+3)--- multiply the first values in both parentheses to get 2x^2.

2. Multiply the outer values (x and 3) to get 3x

3. Multiply the inner values (-2 and 2x) to get -4x

4. Multiply the last values (3 and -2) to get -6.

5. Place all the values together and then simplify by combining like terms...

2x^2 -3x - 4x -6 which simplifies to your final answer of 2x^2-x-6. Hope this helped :))