Answer:
m<AIR = 90 deg
Step-by-step explanation:
I assume the problem contains an error, and that AR is a diameter, not AC.
Look at the diameter of the circle, AR. It passes through the center of the circle, C. You can think of the two radii of the circle, CR and CA, as sides of angle RCA. Since AR is a diameter, and AR is a segment which is part of line AR, rays CR and CA are sides of an angle that lie on a line. That makes the measure of angle RCA 180 deg. Angle RCA is a central angle of circle C since its vertex is the center of the circle.
Angle AIR is an inscribed angle in circle C since its vertex is on the circle itself. If an inscribed angle and a central angle intercept the circle at the same two points, then the measure of the inscribed angle is half the measure of the central angle.
m<AIR = (1/2)m<RCA = (1/2) * 180 = 90
m<AIR = 90 deg
Answer:
60
Step-by-step explanation:
In order to get this answer, we must know that a triangle's angles add up to exactly 180. Also, Angles that intersect will have congruent, opposite sides. The last thing is that a line is = 180 degrees. So, the triangle with the 94 and the 142, you can use that. the angle next to the 142 is going to be 180-142 which is 38 and since the other angle is opposite 94, as well. when you add those up u get 132 and 180-132= 48 which is the missing angle for the far right triangle. then, you get the opposite of that angle, put that in the other triangle, do the same with the 72, and add those up to get 120 and since a triagle adds up to 180, 180-120 = 60. So, 60 is your missing angle. Cheers
Answer:
a. is 3
Step-by-step explanation:
(1/3)* (6+3) = 3
Naw bruv i’m doing the same problems rn and i’m struggling gl tho
