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3 years ago

PLZ HELPPPPP!!!It is due soon if someone could help that would be greattt!

Mathematics

1 answer:

Ganezh [65]3 years ago

5 0

Answer:

1. true

2. False

3. False

4. True

Step-by-step explanation:

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A function is created to represent amount of money spent on lunch if you spent five dollars a day. What restrictions would be ma

sergejj [24]

D. the range would include all real numbers.

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2 years ago

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Divide

IgorC [24]

Answer:

The answer is option 2.

Step-by-step explanation:

Firstly, you must factorize the possible expressions :

$\frac{ {x}^{2} - 2x - 15 }{x - 3} \div \frac{x - 5}{ {x}^{2} - 9 }$

$= \frac{(x - 5)(x + 3)}{x - 3} \div \frac{x - 5}{(x - 3)(x + 3)}$

Next you have to divide by converting to multiplication :

$= \frac{(x - 5)(x + 3)}{x - 3} \times \frac{(x - 3)(x + 3)}{x - 5}$

Lastly, you can cut out the similar expressions :

$= \frac{(x - 5)(x + 3)(x - 3)(x + 3)}{(x - 3)(x - 5)}$

$= {(x + 3)}^{2}$

7 0

3 years ago

12(3+m) A.36m B.36+m C.36+12m D.3m+12m PLEASSSSEEE HELP ASAP 15

kherson [118]

Answer:

C. 36+12m

Step-by-step explanation:

When you distribute a number outside the parenthesis, you multiply it to all numbers nor letters in the parenthesis. Hopes this helps

8 0

2 years ago

Please help me its help.

IgorLugansk [536]

The answer will be 81.

Step-by-step explanation:

just multiple by 3

8 0

2 years ago

Read 2 more answers

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

6 0

3 years ago