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DochEvi [55]
3 years ago
13

PLZ HELPPPPP!!!It is due soon if someone could help that would be greattt!

Mathematics
1 answer:
Ganezh [65]3 years ago
5 0

Answer:

1. true

2. False

3. False

4. True

Step-by-step explanation:

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Perform the following divisions. Be sure all answers are reduced to lowest terms. 5/8 ÷ 2/5 =
UkoKoshka [18]

Here we're dividing a fraction (5/8) by another fraction. We could obtain the same result by inverting the divisor (2/5) and then multiplying (5/8) by (5/2).


The product is 25/16.


Thus, 2/5 divides into 5/8 25/16 times, or 1 9/16 times.

7 0
4 years ago
Rupert is copying some files from his computer to a compact disc, like the one shown above.
My name is Ann [436]

Option B: 11,304 \mathrm{mm} ^2 is the area of the compact disc.

Explanation:

The diameter of the compact disc is 120mm.

To determine the area of the compact disc, let us substitute the values in the area of the circle formula,

A=\pi r^2 where r=\frac{d}{2}

Substituting the value of d in r=\frac{d}{2}, we get,

r=\frac{120}{2} =60

Thus, r=60 and \pi=3.14. Let us substitute these values in A=\pi r^2, we get,

A=3.14\times(60)^2

Simplifying, we have,

A=3.14\times3600

Multiplying, we get,

A=11304mm^2

Thus, the area of the compact disc is 11,304 \mathrm{mm} ^2

Hence, Option B is the correct answer.

3 0
3 years ago
Write an Equation using the following arithmetic sequence: 24, 18, 12
Jlenok [28]

Answer:

24-18=6+6+12

hope this helps you!!

Step-by-step explanation:

7 0
3 years ago
Which fraction is bigger <br> 1 1/6 or 1 4/12
Vedmedyk [2.9K]

Answer:

1 1/6

Step-by-step explanation:

because it takes more to get to 12 than 6

6 0
4 years ago
Read 2 more answers
Find the expansion of tan x about the point X = 0.
yan [13]

Answer:

f(x) = x +\frac{1}{3}x^{3}+....

Step-by-step explanation:

As per the question,

let us consider f(x) = tan(x).

We know that <u>The Maclaurin series is given by:</u>

f(x) = f(0) + \frac{f^{'}(0)}{1!}\cdot x+ \frac{f^{''}(0)}{2!}\cdot x^{2}+\frac{f^{'''}(0)}{3!}\cdot x^{3}+......

So, differentiate the given function 3 times in order to find f'(x), f''(x) and f'''(x).

Therefore,

f'(x) = sec²x

f''(x) = 2 × sec(x) × sec(x)tan(x)

      = 2 × sec²(x) × tan(x)

f'''(x) = 2 × 2 sec²(x) tan(x) tan(x) + 2 sec²(x) × sec²(x)

       = 4sec²(x) tan²(x) + 2sec⁴(x)

       = 6 sec⁴x - 4 sec² x

We then substitute x with 0, and find the values

f(0) = tan 0 = 0

f'(0) =  sec²0 = 1

f''(0) = 2 × sec²(0) × tan(0) = 0

f'''(0) = 6 sec⁴0- 4 sec² 0 = 2

By putting all the values in the Maclaurin series, we get

f(x) = f(0) + \frac{f^{'}(0)}{1!}\cdot x+ \frac{f^{''}(0)}{2!}\cdot x^{2}+\frac{f^{'''}(0)}{3!}\cdot x^{3}+......

f(x) = 0 + \frac{1}{1}\cdot x+ \frac{0}{2}\cdot x^{2}+\frac{2}{6}\cdot x^{3}+......

f(x) = x +\frac{1}{3}x^{3}+....

Therefore, the expansion of tan x at x = 0 is

f(x) = x +\frac{1}{3}x^{3}+.....

8 0
4 years ago
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