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3 years ago

PLEASE HELPPPP!!!!

Physics

2 answers:

ivanzaharov [21]3 years ago

5 0

Answer:

The right option is higher pitch due to change to a higher frequency

Explanation:

Pitch can be defined as the characteristics of a note which enables us to differentiate a high note from a low one.

Frequency: this is the number of oscillation per seconds expressed in Hertz (Hz)

Pitch of a note depends on frequency of a sound wave

I.e as the frequency become high, The higher will be the pitch.

From the question above, when the sound source is moving towards the observer,

Let the frequency of the sound source = f

Let the apparent frequency (frequency which the observer will hear) = f¹

Let the velocity of the source sound = Vₓ

Let the velocity of the observer = V

∴ The apparent frequency (f¹) when the source sound is moving towards the observer = {V/(V-Vₓ)}f

f¹ = {V/(V-Vₓ)}f

since (V-Vₓ ) is less than V, therefore f¹ will be increased.

If f¹ is increased, the pitch is also increased.

The right option is higher pitch due to change to a higher frequency

Tresset [83]3 years ago

3 0

you will hear a higher pitch due to a higher frequency.

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A rocket is fired at a 45° angle, what is the direction of the horizontal velocity vector at the peak height?

Bess [88]

Answer:

B: Horizontally to the left

Explanation:

Horizontal velocity is always constant throughout the entire trajectory of the rocket and acts in the horizontal direction in which the rocket was launched. This is because gravity only acts in the downwards vertical direction.

So in order words at peak height, horizontal velocity is in the horizontal direction in which the rocket was launched.

So if it was to the left, then direction is left but if right, then direction is right.

Looking at the options, the most appropriate will be:

Horizontally to the left

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3 years ago

a hippopotamus produces a pressure of 250000 pa when it is standing on all four feet if the weight of the hippo is 40000 N what

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0.04m²

Explanation:

Given parameters:

Pressure = 250000Pa

Weight = 40000N

Unknown:

Area of each foot = ?

Solution:

Pressure is the force exerted per unit area of a body

Pressure = $\frac{force}{area}$

To find the area;

Area = $\frac{force }{pressure}$

Area = $\frac{40000}{250000}$ = 0.16m²

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the area of each feet = $\frac{0.16}{4}$ = 0.04m²

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3 years ago

Create a list of the different methods or ways that Tonya could communicate the new policy to the staff members

Nuetrik [128]

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3 years ago

A 47-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37 degrees above the

levacccp [35]

Tension in the rope due to applied force will be given as

$F = 142 N$

angle of applied force with horizontal is 37 degree

displacement along the floor = 6.1 m

so here we can use the formula of work done

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now we can plug in all values above

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3 years ago

An object, when pushed with a net force F, has an acceleration of 4 m/s . Now twice the force is applied to an object that has f

hjlf

Answer:

B. 2 m/s

B. Acceleration = 4.05 m/s² and Tension = 297.5 N.

Explanation:

A force is applied on a mass m whose acceleration is 4 m/s

Force = mass × acceleration

a = F/m = 4 m/s

4 m/s = F/m

F = 4 m/s (m)

If Force of 2F is applied on a mass of 4m ; it acceleration is as follows:

2F/4 m = F/ 2m

4m/s (m) / 2m = 2 m/s

a = 2 m/s

Given that

mass $m_1$ = 30 kg

mass $m_2$ = 50 kg

$\mu$ = 0.1

From the question; we can arrive at two cases;

That :

$m_{2} a _ \ {net} }= m_2g - T$ ----- equation (1)

$m_{1} a _ \ {net} }= T - mg sin \theta - F$ ---- equation (2)

50 a = 50 g - T

30 a = T - 30 g sin 30 - 4 × 30 g cos 30

By summation

80 a = $[ 50 - 30 * \frac{1}{2} - 0.1 *30* \frac{\sqrt{3}}{2}]$ g

80 a = 32. 4 × 10 m/s ² (using g as 10m/s²)

80 a = 324 m/s ²

a = 324/80

a = 4.05 m/s²

From equation , replace a with 4.05

50 × 4.05 = 50 × 10 - T

T = 500 -202.5

T =297.5 N

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