Explanation:
the acceleration will be unchanged according to newton second law of motion
Answer:

Explanation:
given,
side of square loop = a = 2.10 cm
Resistance of the wire = 1.30×10⁻² Ω
Length of the loop = c = 1.10 cm
rate of increasing current = 130 A/s






Answer:
Option C
Explanation:
given,
velocity of airplane = 80 m/s
angle with the horizontal = 15°
speed of the ground= ?
when the plane is taking off the horizontal component of the velocity is v cosθ
so,
ground speed of the airplane is = 
=
v = 77.27 m/s
horizontal velocity of the air plane comes out to be 77.27 m/s ≅ 77 m/s
so, the correct option is Option C
Answer:2m/s^2
Explanation:
mass=5kg
Force=10N
Acceleration=force ➗ mass
Acceleration=10 ➗ 5
Acceleration=2m/s^2
Answer:
Speed of block after the bullet emerges = 1.5 m/s
Explanation:
Here momentum is conserved.
Initial momentum = Final momentum.
Mass of bullet = 10 g = 0.01 kg
Initial Velocity of bullet = 300 m/s
Mass of block = 1 kg
Initial Velocity of block = 0 m/s
Final Velocity of bullet = 50% of initial velocity. = 150 m/s
We need to find final velocity of block. Let it be v
We have
Initial momentum = 0.01 x 300 + 1 x 0 = 3 kg m/s
Final momentum = 0.01 x 150 + 1 x v = 1.5 + v
Equating
3 = 1.5 + v
v = 1.5 m/s
Speed of block after the bullet emerges = 1.5 m/s