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solmaris [256]
3 years ago
7

Si se tiene un gato hidráulico y se aplica una fuerza en el Area 1, se refleja otra fuerza en el Area 2, teniendo en cuenta la s

iguiente condición A1 < A2. Podemos afirmar que las fuerzas son:
Physics
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

the forces are proportional to their areas of application

Explanation:

In a hydraulic jack, Pascal's principle is used, that the pressure in an incompressible liquid is the same at the same height, whereby the pressure on both sides of the jack are the same

           P₁ = P₂

the pressure is defined by

            P = F / A

we substitute

           \frac{F_1}{A_1}  = \frac{F_2}{A_2}

           F₂ = \frac{A_2}{A_1} \ F_1

therefore the force is F₂> F₁

Therefore the forces are proportional to their areas of application

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Can someone help me?!!!!!
german
<h2>Hello!</h2>

The answer is:

The first option,  the walker traveled 360m more than the actual distance between the start and the end points.

Why?

Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).

So, calculating we have:

Traveler:

Distance=NorthCoveredDistance+EastCoveredDistance

Distance=4*180m+3*180m=720m+540m=1260m

Actual distance between the start and the end point (displacement):

ActualDistance=\sqrt{NorthDistance+EastDistance}\\\\ActualDistance=\sqrt{NorthDistance^{2} +EastDistance^{2}}\\\\ActualDistance=\sqrt{(720m)^{2} +(540m)^{2}}\\\\ActualDistance=\sqrt{518400m^{2} +291600m^{2}}\\\\ActualDistance=\sqrt{810000m^{2}}=900m

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

DistanceDifference=WalkerCoveredDistance-ActualDistance\\\\DistanceDifference=1260m-900m=360m

Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.

Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.

Have a nice day!

3 0
3 years ago
2. Neutrons have a ____<br> charge.<br> a. positive<br> b. negative<br> c. neutral
AnnyKZ [126]

Answer:

b. negative

Explanation:

neutrons have a negative charge and protons have a proton has a positive charge

3 0
3 years ago
Read 2 more answers
What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?
Veseljchak [2.6K]
A :-) for this question , we should apply
F = ma
Given - F = 12 N
a = 0.20 m/s^2
Solution -
F = ma
12 = m x 0.20
m = 12 by 0.20
m = 60 kg

.:. The mass is 60 kg.
8 0
3 years ago
A father is trying to teach his child to ice skate. As the child stands still, the father pushes him forward with an acceleratio
rjkz [21]

Hi there!

We can use Newton's Second Law:

\Sigma F = ma

∑F = net force (N)

m = mass (kg)

a = acceleration (m/s²)

We are given the mass and acceleration, so:

∑F = 20 · 2 = <u>40 N</u>

4 0
2 years ago
Please help on this one?
diamong [38]

Answer:

ITS C

Explanation:

7 0
3 years ago
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