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solmaris [256]
3 years ago
7

Si se tiene un gato hidráulico y se aplica una fuerza en el Area 1, se refleja otra fuerza en el Area 2, teniendo en cuenta la s

iguiente condición A1 < A2. Podemos afirmar que las fuerzas son:
Physics
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

the forces are proportional to their areas of application

Explanation:

In a hydraulic jack, Pascal's principle is used, that the pressure in an incompressible liquid is the same at the same height, whereby the pressure on both sides of the jack are the same

           P₁ = P₂

the pressure is defined by

            P = F / A

we substitute

           \frac{F_1}{A_1}  = \frac{F_2}{A_2}

           F₂ = \frac{A_2}{A_1} \ F_1

therefore the force is F₂> F₁

Therefore the forces are proportional to their areas of application

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Copper because it contains alot of electricity
6 0
3 years ago
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball initially moving in th
inn [45]

Final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.

<h3>What is conservation of momentum?</h3>

Momentum of an object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity. By the law of conservation of momentum,

m_1u_1 + m_2u_2 = (m_1+m_2)v

Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1, and 2) are used for body 1 and 2 respectively. Rewrite the formula for final velocity as,

v=\dfrac{m_1u_1 + m_2u_2}{(m_1+m_2)}

A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s, has a head-on collision with a 0. 090-kg ball, initially moving in the same direction at a speed of 3.44 m/s. Thus, the initial velocity of the second ball is,

v_{2f}=5.82+3.44+v_{1f}\\v_{2f}=2.38+v_{1f}

Let v1f is the final velocity of first ball. Thus, the initial velocity of the first ball is,

v_{1f}=\dfrac{(0.060)(5.82) + (0.090)(3.44-2.38)}{(0.060)+(0.090)}\\v_{1f}=2.964\rm\; m/s

Thus, final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.

Learn more about the conservation of momentum here;

brainly.com/question/7538238

#SPJ4

4 0
1 year ago
When an automobile moves with constant speed down a highway, most of the power developed by the engine is used to compensate for
sveta [45]

Answer:

F = -4567.40 N

Explanation:

Given that,

The power developed by the engine, P = 196 hp

1 hp = 746 W

196 hp = 146157 W

Speed of the car, v = 32 m/s

Let F is the total friction force acting on the car. The product of force and velocity is called the power developed by the engine. It is given by :

P=-F\times v

F=\dfrac{-P}{v}

F=\dfrac{-146157\ W}{32\ m/s}

F = -4567.40 N

So, the total frictional force acting on the car is 4567.40 N. Hence, this is the required solution.

7 0
3 years ago
This force involves the attraction between objects with mass. (2 points) i need it asap
aev [14]

Answer:

Gravitational Mass

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The amount of gravitational potential energy released as:_________.
nordsb [41]

Answer:

b.it depends on the distance it falls

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