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a_sh-v [17]
3 years ago
15

How does a pendalum conserve energy

Physics
1 answer:
marshall27 [118]3 years ago
5 0
When a pendulum swings, potential energy is transformed into kinetic energy, and then back again to potential energy as the speed and elevation of the pendulum vary during the motion
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How much energy must be added to a bowl of 125 popcorn kernels in order for them to reach a popping temperature of 175°C? Assume
Lisa [10]

Answer:

c) 3176 J

Explanation:

mass of 125 popcorn = 125 x .0001 = . 0125 kg

increase in temperature =  175 - 21 = 154°C

specific heat of popcorn = 1650

heat required to increase temperature

= mass of popcorn x increase in temperature x specific heat

= .0125 x 154 x 1650

=  3176.25 J

8 0
3 years ago
You have been training and can run a mile in 6.5 minutes. How long would it take to run a lap around the outside track, which is
Paha777 [63]

Answer:

1 minute 36.85 seconds

Explanation:

First we need to convert the miles into meters, as the demanded result should be in meters.

1 mile = 1,609.34 meters

Also, 6.5 minutes should be converted into seconds.

1 minute = 60 seconds

6.5 x 60 = 390 seconds

Now we need to divide the miles with the seconds to see how much meters have been run in a second.

1,609.34 / 390 = 4.13 meters

The suggested meters now should be divided with the distance run in one second.

400 / 4.13 = 96.85 seconds

So we get a result of 96.85 seconds, or 1 minute 36.85 seconds.

5 0
3 years ago
What is the amount of displacement of a runner who runs exactly 2 laps around a 400 meter track?
Alex787 [66]
Displacement is the distance and direction from the start point to the end point. Our runner finished exactly where he started. His displacement is zero.
5 0
3 years ago
Read 2 more answers
13. Direct instruction takes place when
jekas [21]
A skill set is explicitly taught or an activity is completed
3 0
3 years ago
The engine of a locomotive exerts a constant force of 8.1*10^5 N to accelerate a train to 68 km/h. Determine the time (in min) t
Bumek [7]

Answer:443.1 s

Explanation:

Given

Engine of a locomotive exerts a force of 8.1\times 10^5 N

Mass of train=1.9\times 10^7

Final speed (v)=68 km/h \approx 18.88 m/s

F=ma

so acceleration(a) =\frac{F}{m}=\frac{8.1\times 10^5}{1.9\times 10^7}

a=0.042631 m/s^2

and acceleration is

a=\frac{v-u}{t}

0.042631=\frac{18.88-0}{t}

t=443.089 \approx 443.1 s

8 0
3 years ago
Read 2 more answers
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