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a_sh-v [17]
3 years ago
15

How does a pendalum conserve energy

Physics
1 answer:
marshall27 [118]3 years ago
5 0
When a pendulum swings, potential energy is transformed into kinetic energy, and then back again to potential energy as the speed and elevation of the pendulum vary during the motion
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A spatially challenged goldfish swims along the x-axis only. Its initial position is 7.8 m. After swimming back and forth a whil
Nostrana [21]

Answer:

  -3.4 m

Explanation:

The displacement is the difference between the final position and the initial position:

  4.4 m - 7.8 m = -3.4 m

6 0
3 years ago
Which two minerals are commercial sources of iron. explain why the answer is a?
vichka [17]

Answer:

Hematite and magnetite

Explanation:

Minerals such as Iron don’t occur alone due to its interaction with other elements. The Iron’s major source is usually through ores such as Hematite, Magnetite, limonite etc.

However Pure magnetite contains 72.4 percent iron and pure hematite contains 69.9 percent. They have the highest percentage of iron thereby making them the main sources.

7 0
3 years ago
What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ
borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

\omega = \sqrt{\frac{k}{m}}

now we have

\omega = \sqrt{\frac{k}{1200}}

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

a = \omega^2 A

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

\frac{1}{2}mv^2 = \frac{1}{2}kA^2

here we know that

v = 85 km/h

v = 85 \times\frac{1000}{3600} = 23.61 m/s

now we have

(1200)(23.61^2) = kA^2

A^2 = \frac{6.68 \times 10^5}{k}

now from above equation of acceleration we have

5.0 g = (\frac{k}{m})\sqrt{\frac{6.68 \times 10^5}{k}}

5.0(9.81) = \sqrt{k}(0.68)

k = 5178.8 N/m

6 0
3 years ago
A 0.5 kg cheeseburger is lobbed at a particularly unhappy customer with a force of 10 N.
aleksley [76]
The acceleration that the cheeseburger experienced is 20 m/s^2.
6 0
3 years ago
If you are watching TV programs from 3:50AM-5:30AM for how much hour you are watching
andreev551 [17]

Answer:

You would be watching tv for 1 hour and 40 mins

Explanation:

How much time take it take for 3:50 am to 5:30

6 0
3 years ago
Read 2 more answers
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