Answer:
The car is going up at a speed of 22.5 mph
Step-by-step explanation:
In this question, we are asked to calculate the speed of a moving car which started moving at an initial velocity for a specific period of time.
To calculate this, we use one of the basic equations of motion;
v = u + at
Where v is the final velocity, u is the initial velocity and t is the time
From the question, we can identify the parameters as follows;
v = ?
u = 10mph
a = 2.5t mph per second for 5 seconds.
Hence a here would be 2.5 * 5 = 12.5
Now, let’s put these values in the equation
v = 10 + 12.5
v = 22.5 mph
Answer:
y= 8th grade class,
y + 24 =160
subtract 24 from both sides
y=136
there are 136 students in the eight grade class
Step-by-step explanation:
Answer:
The sides are 3, 4, and 5
Step-by-step explanation:
Let one side be 'n', if the side lengths are consecutive integers, we have
n
n + 1
and
n + 2 are our side lengths. adding 1 to n gives us the next integer. Adding 2 to n gives use the second consecutive integer to n
The perimeter is 12, so our equation is..
n + (n + 1) + (n + 2) = 12
Now combine like terms and solve..
n + n + 1 + n + 2 = 12
3n + 3 = 12
3n = 9 (subtract 3 from both is sides)
n = 3 (divide by 3 on both sides)
Since n = 3,
n + 1 = 4 and
n + 2 = 5
So the sides are 3, 4, and 5
-.8,2/33,1/11,.4 good luck
