Answer:
29.636363636
Step-by-step explanation:
____________
It is needed at least one more piece of information.
If you call k the ratio a'b' / ab , the addtional information may be tha cb' has the same ratio to cb or that ca' has the same ratio to ca.
It migh also be that the angle at the vertex C has not changed.
Given:
A circle of radius r inscribed in a square.
To find:
The expression for the area of the shaded region.
Solution:
Area of a circle is:

Where, r is the radius of the circle.
Area of a square is:

Where, a is the side of the square.
A circle of radius r inscribed in a square. So, diameter of the circle is equal to the side of the square.

So, the area of the square is:


Now, the area of the shaded region is the difference between the area of the square and the area of the circle.




Therefore, the correct option is (a).
Answer:
i can't see it
Step-by-step explanation:
i click but i still can't
X, x+1
x+x+1=131
2x+1=131
2x=131-1=130
x=130÷2 = 65
the integers are 65 and 66