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lukranit [14]
3 years ago
10

Find the measure of CD. Round to the nearest tenth. Please Help Me I Need It.

Mathematics
1 answer:
Lady_Fox [76]3 years ago
3 0

you need to find the median angle so you take the triangle (A) and solve for the angle using the inverse of sin.(B) take this angle and multiply it by 2 and you should have you arc length I think.

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In sequences 1,7,13,19, ...., each number is 6 more than the number before it. In the sequences 1,9,17,25,...., each number is 8
butalik [34]

Answer:

I think 17, but I'm not sure.

Step-by-step explanation:

here's what I think.

So I don't know how to write it, but I got this,

14 + 2 + 1

6 0
1 year ago
Please help!.......
larisa86 [58]
(f+g) means add the expressions together. combine like terms.
5 {x}^{2}  + 3 {x}^{2}  = 8 {x}^{2}
- 2x + x =  - x
there is no other constant term so the -4 stays as is.
4 0
3 years ago
X + 12/x + 2 = x/x + 8<br> A) X = -4<br> B) X = 8<br> C) X = 6<br> D) X = -6
xxMikexx [17]
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4 0
2 years ago
99999999999999999+99999999999999
lina2011 [118]

Answer:

1.001e+17

Step-by-step explanation:

8 0
2 years ago
(PLESE HELP) Factor the following expression. Simplify your answer.
mars1129 [50]

The factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} }

Since (p + 2)^{\frac{1}{3} } is common, we factor it out. So, we have

(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2}  + 4)

Expanding the bracket, we have

(p + 2)^{\frac{2}{3} } (5p(p^{2}  + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

So, the factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

Learn more about factorization here:

brainly.com/question/11579257

#SPJ1

8 0
1 year ago
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