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Mazyrski [523]
3 years ago
8

3. For the equation-4y = &r, what is the constant of variation? (1 point) ООО 02

Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

3).

- 4y = 8x \\  \frac{y}{x}  =  \frac{8}{ - 4}  \\  \frac{y}{x} =  - 2 \\ y =  - 2x \\ hence \: constant \: is \:  - 2

4).

y \alpha x \\ y = kx \\ where \: k \: is \: the \: constant \: of \: proportionality \\ when \: y = 24 \: and \: x = 8 \\ substitute \: in \: y = kx \\ 24 = 8k \\ k =  \frac{24}{8}  \\ k = 3 \\ value \: of \: constant = 3

If it was by 10, k = 3 by 10

k = 30

5).

general \: equation \: of \: line  \\ y = mx + c \\ but \: m =  \frac{2}{3}  \: and \: c = 9 \\ substitute \: for \: m \: and \: c \: in \: y = mx + c \\ y =  \frac{2}{3} x + 9 \\ alternatively \\ 3y = 2x + 27

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If a cat with short brown hair (llBb) is crossed with a cat with long black hair (Llbb), what is the likelihood that there will
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Bb = brown hair phenotype

bb = black hair phenotype

we see that B = brown hair is the dominant gene while b = black hair is the recessive gene

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ll = short hair, this is a lowercase L

Ll = long hair

In this case, l = short hair is the recessive gene while L = long hair is the dominant gene.

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Check out the diagram below to see the dihybrid crosses for each of the hair color and hair length genotypes. From there, I show all of the genotypes possible for any offspring. Those genotypes are

  • LlBb  = long brown hair (comes up 4 times)
  • Llbb  = long black hair (comes up 4 times)
  • llBb  = short brown hair (comes up 4 times)
  • llbb  = short black hair (comes up 4 times)

-----------------------------------

If we are talking about 1 offspring, then it is not possible for him/her to have both "long black hair AND short brown hair" as the instructions state. So let's consider two offspring instead.

The probability of having long black hair is 4/16 = 1/4 as there are 4 cases of Llbb out of 16 cases total. Similarly, the probability of getting llBb is 4/16 = 1/4 as well, for pretty much the same reasons.

The probability of having both events occur is (1/4)*(1/4) = 1/16

The multiplication of probabilities is valid because the two events are independent.

==============================================

<h3>Final Answer: A) 1/16</h3>

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