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ratelena [41]
3 years ago
9

Please solve no. 8 if you can all but at lesat no. 8​

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

4p'fair x+2is answer in following

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Which option summarizes what gave Chandra Gupta I power
mars1129 [50]

Answer:

Chandra Gupta I, King of India reigned from 320 to about 330 CE and founder of the Gupta empire. He was the grandson of Sri Gupta, the first known leader of the Gupta line. Chandra Gupta I, whose first life is unknown, became the local chief of the kingdom of Magadha parts of the modern state of Bihar.

Step-by-step explanation:

6 0
3 years ago
Which geometric figure are always paraelograms
kolbaska11 [484]
I don’t know I hope u get it
3 0
2 years ago
) Sarah donated one-tenth of her salary to an orphanage, one-third of her salary is spent on food, one-fourth of salary on rent
AleksAgata [21]

Answer:

₹ 4000

Step-by-step explanation:

Sarah's salary =₹ 30000

  • one-tenth of her salary to an orphanage= 1/10*₹ 30000= ₹ 3000
  • one-third of her salary is spent on food= 1/3*₹ 30000= ₹ 10000
  • one-fourth of salary on rent and electricity =1/4*₹ 30000= ₹ 7500
  • one-twentieth of her salary on the telephone= 1/12*₹ 30000= ₹ 2500
  • donated some amount to the Prime Minister's relief fund = x
  • She was left with ₹ 3000.

x= ₹ 30000- (₹ 3000+₹ 10000+₹ 7500+₹ 2500+₹ 3000)= ₹ 4000

8 0
2 years ago
Please help me asap ​
Alex_Xolod [135]
The answer would be C
3 0
2 years ago
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discha
mr Goodwill [35]

Answer:

Step-by-step explanation:

Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by

T(x) = 160-0.05x^2

a. [0, 10]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

The average temperature

= (160 + 155)/2 = 157.5

b. [10, 40]

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (80 + 155)/2 = 117.5

c. [0, 40]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (160 + 80)/2 = 120

6 0
2 years ago
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