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goblinko [34]
3 years ago
14

Write the sum of the numbers as the product of their greatest common factor and another sum.

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0
I am a little bit of time to do with the help you with your family and friends and family
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I have two bags. bag 1 contains 1010 blue marbles, while bag 2 contains 1515 blue marbles. i pick one of the bags at random, and
dimulka [17.4K]
55 blue or red marbles,

55-22 = 33 blue marbles

bag1+bag2= 2525

bag1=.4 

33/55=.6  blue marbles

bag 2=.6

so it is 40% that U choose bag 1 















6 0
3 years ago
classify the polygon by its number of sides. state whether the polygon appears to be regular or not regular
UkoKoshka [18]

Answer: the correct answer is the third option




8 0
3 years ago
Read 2 more answers
The first term of an arithmetic sequence is -5, and the tenth term is 13.
Nitella [24]

Answer:

The common difference is 2

Step-by-step explanation:

The formula for an arithmetic sequence is

an = a1+d(n-1)

a1 = -5

a10 = 13

Substituting n=10 a10=13 and a1 =-5

13 = -5 +d (10-1)

13 = -5 +9d

Add 5 to each side

13+5 = -5+5 +9d

18 = 9d

Divide each side by 9

18/9 = 9d/9

2 =d

7 0
3 years ago
PLEASE HELP<br> Evaluate 6 + 10v – 8w when v=4 &amp; w= -2
BabaBlast [244]

Answer:

6 + 10v – 8w = 62

Step-by-step explanation:

Given the expression

6 + 10v – 8w

as

  • v=4
  • w=-2

substituting the values in the expression

6 + 10v – 8w = 6 + 10(4) - 8(-2)

                      = 6 + 40 + 16

                      = 62

5 0
3 years ago
If x= sin theta then x/√1-x^2 is​
SCORPION-xisa [38]

Well,

Given that x=\sin(\theta),

We can rewrite the equation like,

\dfrac{\sin(\theta)}{\sqrt{1-\sin(\theta)^2}}

Now use, \cos(\theta)^2+\sin(\theta)^2=1 which implies that 1-\sin(\theta)^2=\cos(\theta)^2

That means that,

\dfrac{\sin(\theta)}{\sqrt{1-\sin(\theta)^2}}\Longleftrightarrow\dfrac{\sin(\theta)}{\sqrt{\cos(\theta)^2}}

By def \sqrt{x^2}=x therefore \sqrt{\cos(\theta)^2}=\cos(\theta)

So the fraction now looks like,

\dfrac{\sin(\theta)}{\cos(\theta)}

Which is equal to the identity,

\boxed{\tan(\theta)}=\dfrac{\sin(\theta)}{\cos(\theta)}

Hope this helps.

r3t40

6 0
3 years ago
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