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2 years ago

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A DECK OF CARDS CONTAINS RED CARDS NUMBERED 1,23,4,5,6, BLUE CARDS NUMBERED 1,2,3,4,5, AND GREEN CARDS NMBERED 1,2,3,4. IF A SIN

GLE CARD PICKED AT RANDOM, WHAT IS THE PROBABILITY THT THE CARD HAS AN ODD NUMBER?

2 answers:

Elis [28]2 years ago

7 0

8 over 15........yep......

jeyben [28]2 years ago

5 0

Answer:

5 over nine......................

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Find 3 consecutive even numbers where the product of the smaller two numbers is 40 less than the square of the largest number.

Marina86 [1]

$3\ consecutive\ even\ numbers:\ 2x,2x+2,2x+4\\\\2x(2x+2)+40=(2x+4)^2\\\\
4x^2+4x+40=4x^2+16x+16\\\\
4x^2-4x^2+4x-16x=16-40\\\\-12x=-24\ \ |:(-12)\\\\x=\frac{24}{12}=2\\\\2x=2=4\\\\2x+2=6\\\\2x+4=8\\\\Numbers\ are\ 4,6,8.$

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3 years ago

Find the midpoint of the segment with the following endpoints. (10, 7) and (5, 4)

KatRina [158]

Answer:

$\frac{15}{2} , \frac{11}{2}$

Step-by-step explanation:-

To find the midpoint, the equation we use is:-

$\frac{x1 +x2}{2} , \frac{y1 + y2}{2}$

x1 = 10

x2 = 5

y1 = 7

y2 = 4

Substituting the values in the equation, we get:-

$\frac{10+5}{2} , \frac{7+4}{2}$

Coordinates of the midpoint---> $\frac{15}{2} , \frac{11}{2}$

8 0

3 years ago

Janae bought a new house. The house is quite large, 2500 square feet, and has a nice sized backyard. She bought the house on a f

Bond [772]

Solution :

Rephrasing is defined as to rewriting or expressing the idea or the content in an alternative way.

So rephrasing the question, we get :

Janae bought a new big size house of 2500 square feet with a large size backyard at $ 129,900. Janae wants fence her backyard so that her dog, Lyle can play on the backyard. Before fencing she wants to know the perimeter of the fencing or the size of the yard so that she could fence it. The measures of her yard is :

length : (x-7)

width : (x+2)

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2 years ago

HELP I HAVE NO IDEA WHATS GOING ON PLS HELP

Eduardwww [97]

Answer:

0.182 probability that the Yankees will win when they score fewer than 5 runs

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

When the Yankees score less than 5 runs, either they win, or they lose. The sum of these probabilities is 1.

Probability they lose:

Event A: Scoring fewer than 5 runs.

Event B: Losing

The probability that the Yankees will score 5 or more runs in a game is 0.56.

So 1 - 0.56 = 0.44 probability the Yankees score fewer than 5 runs.

This means that $P(A) = 0.44$

The probability that the Yankees lose and score fewer than 5 runs is 0.36.

This means that $P(A \cap B) = 0.36$

Then the probability they lose is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.36}{0.44} = 0.818$

Probability they win:

p + 0.818 = 1

p = 0.182

0.182 probability that the Yankees will win when they score fewer than 5 runs

3 0

2 years ago

-3 1/2 = 1/2x + 1/2x + c

Alenkasestr [34]

-3/2 = x + c

x = - [(3/2) + c]

7 0

2 years ago

Read 2 more answers