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Tju [1.3M]
2 years ago
12

A DECK OF CARDS CONTAINS RED CARDS NUMBERED 1,23,4,5,6, BLUE CARDS NUMBERED 1,2,3,4,5, AND GREEN CARDS NMBERED 1,2,3,4. IF A SIN

GLE CARD PICKED AT RANDOM, WHAT IS THE PROBABILITY THT THE CARD HAS AN ODD NUMBER?
Mathematics
2 answers:
Elis [28]2 years ago
7 0
8 over 15........yep......
jeyben [28]2 years ago
5 0

Answer:

5 over nine......................

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Please help!!!
xxMikexx [17]

Answer:

A = 1.5 π in² ≈ 4.7 in²

Step-by-step explanation:

the area (A) of the sector is calculated as

A = area of circle × fraction of circle

   = πr² × \frac{\frac{\pi }{3} }{2\pi }

  = π × 3² × \frac{1}{6}

  = 9π × \frac{1}{6}

  =  1.5π in²

  ≈ 4.7 in² ( to the nearest tenth )

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2 years ago
Please please Help me
konstantin123 [22]
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3 years ago
Which expression is equivalent to (x Superscript one-half Baseline y Superscript negative one-fourth Baseline z) Superscript neg
Darina [25.2K]

By using exponent properties, we will get the simplified expression:

x^{-1}*y^{1/2}*z^2

<h3>How to simplify the given expression?</h3>

Here we have the expression:

(x^{1/2}*y^{-1/4}*z)^{-2}

Remember the exponent properties:

(a^n)^m = a^{n*m}

And:

(a*b)^n = (a^n)*(b^n)

So using these two properties, we can rewrite:

(x^{1/2})^{-2}*(y^{-1/4})^{-2}*(z)^{-2}\\\\(x^{-2*1/2})*(y^{-2*-1/4})*(z^{-2}})\\\\x^{-1}*y^{1/2}*z^2

So we conclude that the completely simplified expression is:

x^{-1}*y^{1/2}*z^2

If you want to learn more about exponents:

brainly.com/question/8952483

#SPJ1

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1 year ago
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densk [106]

Answer:

I'm not lol

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find the least common multiple of these two expressions. 15x^7y^3u^8 and 6y^4u^5
snow_tiger [21]

Answer:

30x^7y^4u^8

Step-by-step explanation:

We have been given two expressions 15x^7y^3u^8 and

6y^4u^5

Now we need to find out least common multiple of these two expressions.

First we need to find out what is common factor of both expressions. 15x^7y^3u^8 and

6y^4u^5

Least common multiple means find the expression which can be divided by both expressions.

15 and 6 both goes into 30

so 30 is part of LCM (least common multiple )

Now pickup the highest exponent of each variable.

So we get x^7y^4u^8

Hence required least common multiple is 30x^7y^4u^8

8 0
3 years ago
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