When i calculated it , it says 993.813
Happy New Year from MrBillDoesMath!
Answer:
Proof by ASA congruence postulate. See below
Discussion:
Fact 1 : angle A = angle T (given)
Fact 2: The angles on both sides of point X are equal as vertical angles
are equal.
From these facts it follows that angle M = angle H (as all plane triangles have 180 degrees). Also AM = TH (given) so
In the left triangle In the right triangle
(angle M, side AM, angle A) = (angle H, side TH, angle T)
Hence the triangles have two congruent angles, and congruent sides included between the angles, so they are congruent by ASA.
Thank you,
MrB
Formula is (x-h)2+(y-k)2=r2
Answer:
The polynomial with real coefficients having zeros 2 and 2 - 2i is
x³ - 6x² + 16x - 16 = 0
Step-by-step explanation:
Given that a polynomial has zeros at 2 and 2 - 2i, we want to write this polynomial.
We have
x - 2 = 0
x - (2 - 2i) = 0
=> x - 2 + 2i = 0
Since the polynomial has real coefficients, and 2 - 2i is a zero of the polynomial, the conjugate of 2 - 2i, which is 2 + 2i is also a polynomial.
x - (2 + 2i) = 0
=> x - 2 - 2i = 0
Now,
P(x) = (x - 2)(x - 2 + 2i)(x - 2 - 2i) = 0
= (x - 2)((x - 2)² - (2i)²) = 0
= (x - 2)(x² - 4x + 8) = 0
= x³ - 4x² + 8x - 2x² + 8x - 16 = 0
= x³ - 6x² + 16x - 16 = 0
This is the polynomial required.
she Could have wriiten 2(9+1)^2+6+134 did that help!!!!!!!!!??????????
to check maybe u should try it jsut caculate it :D
