Answer:
Step-by-step explanation:
Let's solve for x.
−3x+2y=−10
Step 1: Add -2y to both sides.
−3x+2y+−2y=−10+−2y
−3x=−2y−10
Step 2: Divide both sides by -3.
−3x
/−3
=
−2y−10
−3
x=
2
/3
y+
10
/3
Answer:
x=
2
/3
y+
10
/3
Answer:
the probability of a Type I error is 0.10
Step-by-step explanation:
Given the data in the question;
significance level ∝ = 0.10
Null H₀ hypothesis is true;
the probability of a Type I error = ?
we know that; a type 1 error is the error of rejecting a Null hypothesis when in reality, it is true. That is false positive.
Hence, our type 1 error will be;
P(rejecting null | null true ) = significance level ∝ = 0.10
Therefore, the probability of a Type I error is 0.10
Answer:
a) 0.0954
b) 0.9045
c) 0.1601
Step-by-step explanation:
We are given the following information:
We treat first-year students having computers as a success.
P(first-year students have computers) = 54.3% = 0.543
Then the number of first year students follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 3
a) P(None have computers)
b) P(At least one has a computer)
c) P(All have computers)