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Natasha2012 [34]
2 years ago
11

List all of the correct numbers rounded to 56.8 when rounded to the nearest tenth don’t forget to put all of the answer

Mathematics
1 answer:
jek_recluse [69]2 years ago
8 0

56.809

56.795

56.832

These all round up to 56.8

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Leo walks his dog 7/8 mile. He walks his dog 3 times a day. How far does Leo walk his dog every day? Show how you can use repeat
alexandr402 [8]
7/8 +7/8 + 7/8 = 21/8 or 2 5/8 miles
7 0
3 years ago
Samuel walks forward 19 steps. He represents this movement with a positive 19. How would he represent the opposite of this numbe
spayn [35]

Answer: -38

Step-by-step explanation:

First he would have to walk back 19 steps to get back to his orginal position, then he would have to further go back another 19 steps.

7 0
3 years ago
A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par
lyudmila [28]

Answer:

a(\frac{1}{5e})=5e

Step-by-step explanation:

we are given equation for position function as

s(t)=tln(5t)

Since, we have to find acceleration

For finding acceleration , we will find second derivative

s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)

=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t

=1\cdot \ln \left(5t\right)+\frac{1}{t}t

s'(t)=\ln \left(5t\right)+1

now, we can find derivative again

s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)

=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)

=\frac{1}{t}+0

a(t)=\frac{1}{t}

Firstly, we will set velocity =0

and then we can solve for t

v(t)=s'(t)=\ln \left(5t\right)+1=0

we get

t=\frac{1}{5e}

now, we can plug that into acceleration

and we get

a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}

a(\frac{1}{5e})=5e


5 0
3 years ago
Please help me idk this
d1i1m1o1n [39]

Step-by-step explanation:

120 because angle a and c are the same

5 0
3 years ago
Read 2 more answers
35 mph to feet per hour
exis [7]
25miles/hour
1 mile=5280 feet
25*5280ft/hour
132,000ft/hour

Hope this helps!
5 0
3 years ago
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