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3 years ago

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A wire of resistance 7 ohms and length 2.8 m is bent into a circle and is concentric with a solenoid in which the magnetic flux

changes from 6 T·m2 to 4 T·m2 in 0.2 seconds. What is the emf in the wire? V What is the non-Coulomb electric field in the wire? V/m What is the current in the wire?

1 answer:

Serggg [28]3 years ago

7 0

Answer:

The emf, electric field and the current in the wire are 10 V, 3.57 V/m and 1.43 A.

Explanation:

Given that,

Resistance = 7 ohms

Length = 2.8 m

Time t =0.2

We need to calculate the change in magnetic flux

Using formula of induced emf

$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{6-4}{0.2}$

$\epsilon=10\ V$

We need to calculate the electric field in the wire

Using formula of electric field

$E=\dfrac{V}{l}$

$E=\dfrac{10}{2.8}$

$E=3.57\ V/m$

We need to calculate the current in the wire,

Using formula of ohm's law

$V=IR$

$I=\dfrac{V}{R}$

Put the value into the formula

$I=\dfrac{10}{7}$

$I=1.43\ A$

Hence, The emf, electric field and the current in the wire are 10 V, 3.57 V/m and 1.43 A.

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Answer:

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notie the volume formula has two unknowns or variables, so we need to relate the radius with the height with an equation we can use to rewrite our volume formula in terms of either the radius or the height. Since in this case the problem wants us to find the rate of change over time of the height of the gasoline tank, we will need to rewrite our formula in terms of the height h.

If we take a look at a cross section of the cone, we can see that we can use similar triangles to find the equation we are looking for. When using similar triangles we get:

$\frac {r}{h}=\frac{4}{5}$

When solving for r, we get:

$r=\frac{4}{5}h$

so we can substitute this into our volume of a cone formula:

$V_{cone}=\frac{1}{3} \pi (\frac{4}{5}h)^{2}h$

which simplifies to:

$V_{cone}=\frac{1}{3} \pi (\frac{16}{25}h^{2})h$

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So now we can proceed and find the partial derivative over time of each of the sides of the equation, so we get:

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Now we can substitute the provided values into our equation. So we get:

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<span>anwser will be

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Next working equation is

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the anwser will be
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F =320.11 Newtons

Hope this helps. </span><span>
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