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PtichkaEL [24]
3 years ago
9

Order these sounds from loudest (1)

Physics
2 answers:
xz_007 [3.2K]3 years ago
7 0

Answer:

1. Airplane

2. Crowd at sporting

3. Event

4. Rainfall

5. Whisper

amm18123 years ago
7 0

Answer:

Airplane:  1

Whisper:  4

Crowd at sporting event:  2

Rainfall: 3

Explanation:

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Which term describes a model in which a charge takes up no space and acts uniformly on its surroundings?
SVETLANKA909090 [29]
It's called point charge. Hope this helps.
7 0
4 years ago
Read 2 more answers
A copper cable needs to carry a current of 160 A with a power loss of only 2.0 W/m. What is the required radius of the copper ca
lesantik [10]

Answer:

The radius of the cable is 0.0083 m or 8.3 mm.

Explanation:

The resistance of copper cable of 1 meter length will be given by

R_{cable} = \frac{\rho \times l}{a}    ....     (i)

where the resistivity of copper is \rho = 1.7 \times 10^{-8} \Omega.m , and l is the length of the wire which is considered to be 1m, and a is the cross sectional area of the wire in m^{2}.

From the formula of power we know that, P = I^2 R    ....    (ii)

Therefore 2 W/m  = (160)^2 \times R     ....     (iii)  

where  the resistance,R, actually means the resistance of the cable per meter.

Therefore R ( resistance of cable per meter)

= \frac{2}{160^2}  = 7.812 \times 10^{-5} ohms / meter.       ....    (iv)

Therefore from (i)

7.812 \times 10^{-5} = \frac{1.7 \times 10^{-8} \times 1}{a}  = \frac{1.7 \times 10^{-8} \times 1}{\pi r^{2} }       .....     (v)

where cross sectional area of the cable, a  = \pi r^2,

where r is the radius of the cable, and length of cable,l = 1m.

Therefore r  = \sqrt{\frac{ 1.7 \times 10^{-8}}{\pi \times 7.812 \times 10^{-5} } }  =  0.0083m = 8.3 mm

5 0
4 years ago
Please help me on this!
alexgriva [62]

Answer:

3rd answer

Explanation:

compare the total amount of time for each student

8 0
3 years ago
A capacitor with capacitance (c) = 4.50 μf is connected to a 12.0 v battery. what is the magnitude of the charge on each of the
svet-max [94.6K]

<u>Answer:</u> The charge on each plates is 54\mu C .

<u>Explanation:</u>

The magnitude of charge that flows through the plates is directly dependent on the capacitance and the voltage flowing through the plates.

Mathematically,

Q=CV

where,

Q = charge flowing = ? C

C = capacitance = 4.5\mu F=4.5\times 10^{-6}F    (Conversion Factor: 1\mu F=10^{-6}F)

V = Voltage across the plates = 12 V

Putting values in above equation, we get:

Q=4.5\times 10^{-6}F\times 12V=54\times 10^{-6}C=54\mu C

Hence, the charge on each plates is 54\mu C .

8 0
4 years ago
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4. What property of metals make them good conductors of heat?
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The metal’s feely moving sea of electrons
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3 years ago
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