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3 years ago

Order these sounds from loudest (1)

Physics

2 answers:

xz_007 [3.2K]3 years ago

7 0

Answer:

1. Airplane

2. Crowd at sporting

3. Event

4. Rainfall

5. Whisper

amm18123 years ago

7 0

Answer:

Airplane: 1

Whisper: 4

Crowd at sporting event: 2

Rainfall: 3

Explanation:

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A machine is supplied Energy at a rate of 4000 W and does useful work at a rate of 3760 W. What is the efficiency of the machine

ICE Princess25 [194]

The efficiency of a machine is the ratio between the output power and the power in input:
$\epsilon = \frac{P_{out}}{P_{in}}$
in our problem, the output power is 3760 W while the input power is 4000 W, so the efficiency is
$\epsilon = \frac{3760 W}{4000 W} =0.94$
So the efficiency of the machine is 94%.

6 0

3 years ago

Read 2 more answers

A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa

vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo = (16.1*25- 160) ft / 5s = 48.5 ft/s

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

We now need the time at which y(t') = -64 ft

-64 = -16.1*t'^2 + 48.5*t'

By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0

4 years ago

A block is launched up a frictionless 40° slope with an initial speed v and reaches a maximum vertical height h. The same block

Strike441 [17]

Answer: 1. h

Explanation:

The block would reach exactly the same height from the ground. It would travel a greater distance away from the source, but the height away from the earth would remain the same as you are giving it the same energy each time. Therefore, it will reach the same gravitation potential energy.

Another approach to look at it this is seeing it when the Block moves up the slope, its kinetic energy decreases and the potential energy increases. In both cases, the kinetic energy decreases by same amount, therefore the block rises to same height H.

Try to use the formula;

1/2MV2 = mgh

Where V = √(2gh)

I hope this helps