Only certain organizations survive in the wild or nature,....
Answer:
5525 N/C
Explanation:
Magnitude of electric field ( E ) = 3500 N/c
Direction of electric field : positive X axis
point charge ( q ) = -9.0 * 10^-9
<u>Calculate the Magnitude of the net electric field at (a) x = -0.20 m</u>
Magnitude = 5525 N/C
Electric field due to q = ( 9 * 10^9 * 9 * 10^-9 ) / ( -0.2 )^2
= 81 / 0.04 = 2025 N/c
<em>Therefore the magnitude of the net electric field </em>
= 2025 + 3500
= 5525 N/C
Answer:
it is given that the water is to be compressed by 0.10%. Therefore, the pressure on the water should be
2.2 × 10^6 Nm ^ -2 .
To solve this problem we should apply Newton's third law for which it is defined that there must be an equal reaction in the opposite direction.
From this law, if Car A generates a force on car B, that car must have opposed a force exactly the same but in the opposite direction. The car A moved to the left and generates a force of 900lb so the magnitude of the force in the car B is also 900lb but to the right (opposite direction to the first car)
The correct option is 900lb to the right.
