
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Rectangular prism the two square on the end have 4 vertices each
The explicit formula for calculating the sum is

The sum of the nth term of a sequence is expressed as;

a is the first term
d is the common difference
n is the number of terms
For the sequence 0 + 1 + 2 + 3 +...

Similarly for the sequence:
1 + 2+ 3 + 4+...

Taking the product of the sum to get the explicit formula for calculating the sum

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