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3 years ago

the markup on a restaurant meal is 250%. a meal cost $7.30 to produce. how much will the customer be charged before tax and tip?

1 answer:

6 0

The cost of the meal would be $18.25. You can find this answer by multiplying 7.30 by 2.5, since the decimal form of 250% is 2.5.

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3 years ago

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3 years ago

What is the equation of the line in the graph

iren [92.7K]

Always, ALWAYS remeber this format: y = mx + b

In this equation, 'm' is the slope, and 'b' is the y-intercept

When you're trying to find a slope, remember that the equation is $\frac{rise}{run}$

When finding the rise and run, look at two points that are on the graph AND on the line as well. Essentially, make sure the points you're using are integers.

In this, case, the rise is -3, and the run is 2. This means that the slope is $\frac{-3}{2}$

Now we have the first part of our equation:

y = - $\frac{3}{2}$ + b

But wait! How do we find b?

Sometimes you have to input x in order to find it, but only when you're not supplied with a graph. In this case, all you have to do is look!

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3 years ago

The net change for a certain stock is the dollar value change in the stock's closing price from the previous day's closing price

Natali [406]

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3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

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2 years ago