The mode would be 17, it’s the number that appears the most. I’m not rewriting it though
Answer: Option C
Step-by-step explanation:
If the graph of the function
represents the transformations made to the graph of
then, by definition:
If
the graph moves vertically upwards.
If
the graph moves vertically down
In this problem we have the function
and our parent function is 
therefore it is true that
Therefore the graph of
is moves vertically upwards by a factor of 5 units.
The answer is the Option C: "The graph of g(x) is the graph of f(x) shifted up 5 units"
C. 4258.44 yd3 if u multiple then bring it down thre subtract
<u>Answer: </u>
sec squared 55 – tan squared 55 = 1
<u>Explanation:</u>
Given, sec square 55 – tan squared 55
We know that,

And,

where Ө is the angle
Substituting the values

Solving,

According to Pythagoras theorem,

Putting this in the equation;
squared 55 - tan squared 55 =

Therefore, sec squared 55 – tan squared 55 = 1
Answer:
Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.
Step-by-step explanation:
Recall that the direct formula of a geometric sequence is given by:

Where <em>T</em>ₙ<em> </em>is the <em>n</em>th term, <em>a</em> is the initial term, and <em>r</em> is the common ratio.
We are given that the fifth term <em>T</em>₅ = 96 and the eighth term <em>T</em>₈ = 768. In other words:

Substitute and simplify:

We can rewrite the second equation as:

Substitute:

Hence:
![\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B768%7D%7B96%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B8%7D%20%3D%202)
So, the common ratio <em>r</em> is two.
Using the first equation, we can solve for the initial term:

In conclusion, of the given geometric sequence, the first term <em>a</em> is 6 and its common ratio <em>r</em> is 2.