The ordered pairs of the solution to the system of equation are [(3, 6), (-3, 18)]
<h3>System of equations</h3>
Given the following system of equations expressed as:
f(x) = x² - 2x + 3 and f(x) = -2x + 12
Since they are both function of x, hence;
x² - 2x + 3 = -2x + 12
x² - 2x + 3 + 2x - 12 = 0
x² - 9 = 0
x² = 9
x = ±√9
x = ±3
If x = 3
f(x) = -2(3) + 12
f(x) = 6
If x = -3
f(x) = -2(-3) + 12
f(x) =18
Hence the ordered pairs of the solution to the system of equation are [(3, 6), (-3, 18)]
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Answer:
The correct answer is C.
Step-by-step explanation:
The given equation is;
This implies that;
Let us write in Cartesian coordinates by substituting;
Square both sides;
This implies that;
This is an equation of a parabola that opens upwards with a y-intercept of 
.
The correct choice is C
Answer:
Bottom left
Step-by-step explanation:
It shows that x is a unpredictable number but also show the value of 3 and 7
Answer:
5
Step-by-step explanation:
All the edges of a cube have the same length, and the volume of a cube is the length of an edge taken to the third power. So the length of the edge of a cube with a volume of 125 is 5.
Answer:
b(b/a)^2
Step-by-step explanation:
Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then
b = a - (p% × a) = a(1-p%)
b/a = 1 - p%
p% = 1 - b/a = (a-b)/a
Let the worth of the car on December 31, 2012 be c
then
c = b - (b × p%) = b(1-p%)
Let the worth of the car on December 31, 2013 be d
then
d = c - (c × p%)
d = c(1-p%)
d = b(1-p%)(1-p%)
d = b(1-p%)^2
d = b(1- (a-b)/a)^2
d = b((a-a+b)/a)^2
d = b(b/a)^2 = b^3/a^2
The car's worth on December 31, 2013 = b(b/a)^2 = b^3/a^2
