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3 years ago

How do you find square root ?

Mathematics

2 answers:

timama [110]3 years ago

7 0

Answer:

Finding the square root of a number is the inverse operation of squaring that number. Remember, the square of a number is that number times itself.

iren [92.7K]3 years ago

6 0

You have to memorize the perfect squares but there are a lot of numbers that aren’t a perfect square. The best and easiest way is for you to use the square root button on the calculator or get the number and raise it to the 1/2 power

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A triangle has two sides of lengths 7 and 9.what value could the length of the third side be?

Diano4ka-milaya [45]

The side length has to be between 2 (=9-7) and 16 (=9+7). In both these corner cases the triangle will have collapsed to a line.

So the correct answers are B,C,D and E, and F is a corner case. Theoretically I suppose you have to count F in as a valid answer.

7 0

3 years ago

Help meh... please. I’m doing a test with my friends and we all need help

Inessa [10]

Answer:

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3 years ago

Read 2 more answers

Perpendicular to the line y =6 - 3x; passes through (-3, -1)

madam [21]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

Perpendicular lines

Perpendicular lines have slopes whose product is -1. In other words, to find a line that is perpendicular to a given line, the new line must have a that is the opposite reciprocal of the original line.

Passing through a point
Additionally, if a line contains a point, then the point must be a solution to the equation (meaning, when you plug in the "x" and "y", the equation must be true).

Finding our perpendicular line

Work on slope first

To find the slope of the original line, rewrite the original line in slope-intercept form: $y=mx+b$

$y=6-3x\\y=6+(-3x)\\y=(-3x)+6\\y=-3x+6\\y=-\frac{3}{1}x+6$

In this form, the slope is the number multiplied to the "x", so the original slope is -3/1.

Thus, the slope of the new perpendicular line will be the opposite reciprocal of -3/1 ... which is 1/3.

Writing what we do know about the new perpendicular line, we have $y=\frac{1}{3}x+b$

Making sure it passes through the point
This new line is also supposed to contain the point (-3,-1), so (-3,-1) must be a solution to the equation, for whatever constant-value the "b" is. To find out the "b", substitute the known quantities, and solve:

$-1=\frac{1}{3} (-3)+b\\-1=-1+b\\(-1)+1=(-1+b)+1\\0=b$

Substituting this into our equation:

$y=\frac{1}{3}x+(0)\\y=\frac{1}{3}x$

Conclusion

So, the equation for a line that is perpendicular to the original line $y=6-3x$ , and that also passes through (-3,-1) is $y=\frac{1}{3}x$

6 0

2 years ago

What is the slope of the line 3x-4y=7

elena55 [62]

Rearrange it
3x-4y=7
3x-7=4y
y= $\frac{3}{4}$ x - $\frac{7}{4}$
slope is $\frac{3}{4}$

3 0

3 years ago

What is the slope of the line represented by the equation y = –2/3 – 5x

Nookie1986 [14]

The equation is of the form y = mx + c, where m is the slope and c just a constant. In this example, m=-5 and c=-2/3, so the slope is -5. The -2/3 is just a vertical offset and is irrelevant.

6 0

3 years ago