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3 years ago

Only answer 28 ( I added this parentheses so that the thing would accept my question)

Mathematics

1 answer:

avanturin [10]3 years ago

3 0

Answer:

(a). Number of protons in a chlorine atom = 17

(b). Atomic number of sodium = 11

Step-by-step explanation:

Let the number of protons in a sodium atom = x

Then, the number of protons in a chlorine atom = x + 6

Now, it is given that the atomic number of an element is equal to the number of protons per atom.

So, atomic number of sodium (Na) = x

Atomic number of chlorine (Cl) = x + 6

It is given that the atomic number of chlorine is 5 less than twice the atomic number of sodium.

∴ atomic number of chlorine (Cl) = 2 × atomic number of sodium (Na) - 5

⇒ x + 6 = 2x - 5

⇒ x - 2x = -5 - 6

⇒ -x = -11

Cancelling the minus sign from both sides, we get

x = 11

(a). Number of protons in a chlorine atom = x + 6

= 11 + 6 (∵ x = 11)

= 17

(b). Atomic number of sodium = x = 11

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2.A production process manufactures items with weights that are normally distributed with mean 10 pounds and standard deviation

Vesna [10]

Answer:

Step-by-step explanation:

Given that:

population mean = 10

standard deviation = 0.1

sample mean = 9.8 < x > 10.2

The z score can be computed as:

$z = \dfrac{\bar x - \mu}{\sigma}$

if x > 10.2

$z = \dfrac{10.2- 10}{0.1}$

$z = \dfrac{0.2}{0.1}$

z = 2

If x < 9.8

$z = \dfrac{9.8- 10}{0.1}$

$z = \dfrac{-0.2}{0.1}$

z = -2

The p-value = P (z ≤ 2) + P (z ≥ 2)

The p-value = P (z ≤ 2) + ( 1 - P (z ≥ 2)

p-value = 0.022750 +(1 - 0.97725)

p-value = 0.022750 + 0.022750

p-value = 0.0455

Therefore; the probability of defectives = 4.55%

the probability of acceptable = 1 - the probability of defectives

the probability of acceptable = 1 - 0.0455

the probability of acceptable = 0.9545

the probability of acceptable = 95.45%

4.55% are defective or 95.45% is acceptable.

sampling distribution of proportions:

sample size n=1000

p = 0.0455

The z - score for this distribution at most 5% of the items is;

$z = \dfrac{0.05 - 0.0455}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}$

$z = \dfrac{0.0045}{\sqrt{\dfrac{0.04342975}{1000}}}$

$z = \dfrac{0.0045}{\sqrt{4.342975 \times 10^{-5}}}$

z = 0.6828

The p-value = P(z ≤ 0.6828)

From the z tables

p-value = 0.7526

Thus, the probability that at most 5% of the items in a given batch will be defective = 0.7526

The z - score for this distribution for at least 85% of the items is;

$z = \dfrac{0.85 - 0.9545}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}$

$z = \dfrac{-0.1045}{\sqrt{\dfrac{0.04342975}{1000}}}$

z = −15.86

p-value = P(z ≥ -15.86)

p-value = 1 - P(z < -15.86)

p-value = 1 - 0

p-value = 1

Thus, the probability that at least 85% of these items in a given batch will be acceptable = 1

6 0

3 years ago