3 years ago

If A ABC-A DEF, find mZA. O 67 O 54 59 O 69

Mathematics

1 answer:

marysya [2.9K]3 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

The average cost for a gallon of gasoline increased from $2.56 one year to $3.18 the next year. What is the percent of increase,

Kitty [74]

From 2.56 to 3.18; 3.18-2.56=0.62 increased
so if 2.56 represented 100%
0.62 represents ? %
cross multiply
?%= 0.62·100/2.56=24.21875 which rounded to the nearest whole is 24%
Answer is B).

7 0

3 years ago

Read 2 more answers

What is j(4) if j(m)=2^m-1

Lady_Fox [76]

2^4-1 so 2•2•2•2=16 and 16-1 is 15

5 0

2 years ago

PLEASE ANSWER THIS I BEG FOR YOUR MERCY!!!!!!!!!!!! if you dont know....dont answer

Andreyy89

Answer:

the answer is the second choice

Step-by-step explanation:

hopefully this helps :)

8 0

2 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

3 years ago

So i called a friend a brat as a joke but shes mad at me now what do i do

Dmitry_Shevchenko [17]

You could apologize

3 0

2 years ago