Since V = (4/3) * pi * R^3
If R is halved, V' will reduce by a ratio of (1/2)^3 = 1/8
So V' = (1/8)V
i have no clue what so ever -_-
Step 1: All angles in a triangle must add up to 180! Therefore, in the upper triangle, add up the two you know 85+35=120 so the missing angle is 60.
Step 2: Bottom triangle. Your new angle above (60) is the pair of the opposite angle - so it too is 60. So now you know 2 of the 3 angles: 60+64=124 Subtract that from 180 and you get 56...which is the answer for ?
Answer:
![A=2\sqrt{14}\ units^2](https://tex.z-dn.net/?f=A%3D2%5Csqrt%7B14%7D%5C%20units%5E2)
Step-by-step explanation:
we know that
Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.
so
![A=\sqrt{s(s-a)(s-b)(s-c)}](https://tex.z-dn.net/?f=A%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D)
where
a, b and c are the length sides of triangle
s is the semi-perimeter of triangle
we have
![a=5\ units,b=6\ units,c=3\ units](https://tex.z-dn.net/?f=a%3D5%5C%20units%2Cb%3D6%5C%20units%2Cc%3D3%5C%20units)
<em>Find the semi-perimeter s
</em>
s=![\frac{5+6+3}{2}=7\ units](https://tex.z-dn.net/?f=%5Cfrac%7B5%2B6%2B3%7D%7B2%7D%3D7%5C%20units)
Find the area of triangle
![A=\sqrt{7(7-5)(7-6)(7-3)}](https://tex.z-dn.net/?f=A%3D%5Csqrt%7B7%287-5%29%287-6%29%287-3%29%7D)
![A=\sqrt{7(2)(1)(4)}](https://tex.z-dn.net/?f=A%3D%5Csqrt%7B7%282%29%281%29%284%29%7D)
![A=\sqrt{56}\ units^2](https://tex.z-dn.net/?f=A%3D%5Csqrt%7B56%7D%5C%20units%5E2)
simplify
![A=2\sqrt{14}\ units^2](https://tex.z-dn.net/?f=A%3D2%5Csqrt%7B14%7D%5C%20units%5E2)