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blondinia [14]
3 years ago
10

What is the GCF of 30 and 49 ?

Mathematics
1 answer:
horsena [70]3 years ago
8 0

The GCF of 30 and 49 is 1.

Steps to find GCF: <span><span>Find the prime factorization of 30
30 = 2 × 3 × 5 </span><span>Find the prime factorization of 49
49 = 7 × 7 </span><span>Multiply all the common factors obtained in steps i) and ii) above to find the GCF:

GCF = 1</span></span>
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SVETLANKA909090 [29]

Answer:

Given that:

L(t) = 52\sin(\frac{2 \pi t}{365})+728

where

L(t) represents the length of each day(in minutes) and t represents the number of days.

Substitute the value of L(t) = 750 minutes we get;

750= 52\sin(\frac{2 \pi t}{365})+728

Subtract 728 from both sides we get;

22= 52\sin(\frac{2 \pi t}{365})

Divide both sides by 52 we get;

0.42307692352= \sin(\frac{2 \pi t}{365})

or

\frac{2 \pi t}{365} = \sin^{-1} (0.42307692352)

Simplify:

\frac{2 \pi t}{365} =0.43683845

or

t = \frac{365 \times 0.43683854}{2 \times \pi} = \frac{365 \times 0.43683854}{2 \times 3.14}

Simplify:

t \approx 25 days

Therefore, the first day after the spring equinox that the day length is 750 minutes, is 25 days

4 0
3 years ago
Read 2 more answers
Use a calculator to find the r-value of these data. Round the value to three decimal places.
Sindrei [870]

Answer:

-0.985

Step-by-step explanation:

Refer to the image below for explanation:

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2 years ago
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1500 soldiers arrive at a training camp. A few soldiers desert the camp. The drill sergeants divide the remaining soldiers into
iren [92.7K]

Answer:

The number of deserters is 34.

Step-by-step explanation:

We have to calculate the number of desertors in a group of 1500 soldiers.

The sergeant divides in groups of different numbers and count the lefts over.

If he divide in groups of 5, he has on left over. The amount of soldiers grouped has to end in 5 or 0, so the total amount of soldiers has to end in 1 or 6.

If he divide in groups of 7, there are three left over. If we take 3, the number of soldiers gruoped in 7 has to end in 8 or 3. The only numbers bigger than 1400 that end in 8 or 3 and have 7 as common divider are 1428 and 1463.

If we add the 3 soldiers left over, we have 1431 and 1466 as the only possible amount of soldiers applying to the two conditions stated until now.

If he divide in groups of 11, there are three left over. We can test with the 2 numbers we stay:

(1431-3)/11=1428/11=129.82\\\\(1466-3)/11=1463/11=133

As only 1466 gives a possible result (no decimals), this is the amount of soldiers left.

The deserters are 34:

D=1500-1466=34

6 0
3 years ago
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To solve this problem using substitution, we need to set x equal to a value and substitute it into the other equation.

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Now that we know y is -1, we can substitute it back into the equation to find x:

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0.7×5=3.5 or 3 1/2

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