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Alex
3 years ago
10

(a(a+b)-b(a+b) factorizacion

Mathematics
1 answer:
RSB [31]3 years ago
5 0
\left(a\left(a+b\right)-b\left(a+b\right)\right)

We take:
a\left(a+b\right)
And aply the law of the exponents:
=a^2+ab
we do the same process at the other side and we get:
=a^2+ab-ab-b^2
Now:
+ab-ab=0
So we get that:
=a^2-b^2
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Answer:

\text{Average diameter is 1.65 mm and we decide that it is not 1.65 mm.}                

Step-by-step explanation:

We are given the following in the question:

The needle size should not be too big and too small.

The diameter of the needle should be 1.65 mm.

We design the null and the alternate hypothesis

H_{0}: \mu = 1.65\text{ mm}\\H_A: \mu \neq 1.65\text{ mm}

Sample size, n = 35

Sample mean, \bar{x} = 1.64 mm

Sample standard deviation, s = 0.07 mm

Type I error:

  • It is the error of rejecting the null hypothesis when it is true.
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Thus, type I error in this study would mean we reject the null hypothesis that the average diameter is 1.65 mm but actually the average diameters of the needle is 1.65 mm.

Thus, average diameter is 1.65 mm and we decide that it is not 1.65 mm.

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Step-by-step explanation:

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