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Oxana [17]
3 years ago
13

I will mark brainliest for accurate answer!

Mathematics
2 answers:
katrin [286]3 years ago
8 0

Answer:

C

Step-by-step explanation:

(x,y)=(0.5,-1)

So you go right 0.5 along the x axis cos its positive and down 1 on the y cos it negative

icang [17]3 years ago
6 0

Answer:

The answer is C

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kondor19780726 [428]
The quadratic formula is -b plus minus the square root of b^2-4ac all over 2a.
Here, a=1, b=13, and c=30.
The only option that fills in the values correctly is D
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3 years ago
(m-2)5 = m3<br> True or False
AleksAgata [21]
The answer is true trust just had this
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3 years ago
Hi! If you could please do my assignment, I'd be grateful! I'll also mark brainliest, giving thanks, and hearts for the best. (
KonstantinChe [14]

Answer:

False

False

True

False

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Step-by-step explanation:

I hope this helps!

8 0
3 years ago
Help me please thanks :)
Softa [21]
The answers should be A and E! Hope it helps!
8 0
3 years ago
What is the equation of the circle that has its center at -26,120 and passed through the origin
OlgaM077 [116]

well, first off let's check those two points, we know it's centerd at (-26 , 120) and we also know it passes through (0 , 0), so the distance between those two points is its radius

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{-26}~,~\stackrel{y_2}{120})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{(~~-26 - 0~~)^2 + (~~120 - 0~~)^2} \implies r=\sqrt{(-26)^2 + (120 )^2} \\\\\\ r=\sqrt{( -26 )^2 + ( 120 )^2} \implies r=\sqrt{ 676 + 14400 } \implies r=\sqrt{ 15076 } \\\\[-0.35em] ~\dotfill

\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill

3 0
1 year ago
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