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Setler [38]
3 years ago
14

As Evin is driving her car, she notices that after 1 hour her gas tank has 7.25 gallons left and after 4 hours of driving, it ha

s 3.5 gallons of gas left in it. What is the rate at which her car is using gas.
Mathematics
1 answer:
kompoz [17]3 years ago
5 0

Answer:

7.25 per hour

Step-by-step explanation:

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What is this? Attached
andrew-mc [135]
It's a function of function f(g(x))

f(x) = (x-3)/x  and g(x) =5x-4

Just plug the value (5x-4) in x of f(x)

f(x) = [(5x-4) -3] / (5x-4) ==== f(x) = (5x-7)/(5x-4)


The domain are all the value of x different from 4/5 (or the number that render the denominator nil.

In short 5x-4 ≠ 0 or x≠ 4/5

Domain ={x/x ≠5/4}
5 0
3 years ago
WILL MARK BRAINLIEST!!!Triangle RST has vertices located at R (2,3), S (4,4), and T (5,0)
shtirl [24]

Answer:

Answers:

k = 13The smallest zero or root is x = -10

===============================

Work Shown:

note: you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

Step-by-step explanation:

If this is wrong i am so sorry i tried my best.

5 0
4 years ago
(correct answers only)
deff fn [24]

Answer:

2.7 s  (1 d.p.)

Step-by-step explanation:

Use the <u>Constant Acceleration Equations</u> where:

  • s = displacement in meters
  • u = initial speed in m/s
  • v = final speed in m/s
  • a = acceleration in m/s²
  • t = time in s (seconds)

Given:

  • s = 55 m
  • u = 11.8 m/s
  • a = 6.39 m/s²

\begin{aligned}\text{Using }s & =ut+\dfrac{1}{2}at^2\\\implies 55 & =11.8t+\dfrac{1}{2}(6.39)t^2\end{aligned}

Rearrange the equation to equal zero:

\implies 3.195t^2+11.8t-55=0

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Use the quadratic equation to solve for t:

\implies a=3.195, \quad b=11.8, \quad c=-55

\implies t=\dfrac{-11.8 \pm \sqrt{11.8^2-4(3.195)(-55)} }{2(3.195)}

\implies t=2.694780675, -6.388051411

As time is <u>positive</u>:

\implies t=2.694780675... \:\text{s}

\implies t=2.7 \: \text{s (1 d.p.)}

Learn more about SUVAT equations here:

brainly.com/question/26241670

4 0
2 years ago
Read 2 more answers
Help!!!!!! need help with all! will give brainliest!!!!!!!!
castortr0y [4]

CD=21

DE=16

CE=21#7:

(3x-4)+(9x+17)+(6x-31)=180 <- sum of angles in a triangle

18x-18x=180 <- Simplify

18x=198

x=11 now substitute, m<A=9*11+17, m<A=116

#8:

(10x-23)=(7x-26)+(5x-27) <- Exterior angle of triangle

10x-23=12x-53

x=30; substitute, m<A=30*5-27, m<A=123

#9:

m<R=74 <- Base angles therom

m<Q+74*2=180 <- Sum of angles in triangle

m<Q=32 <- Simplify

#10:

m<E=m<G <- Base angles therom

2m<E+106=180 <-Sum of angles in triangle

m<E=m<G=37

#11:

m<A=180-48*2

m<A=84

Triangle is isosceles so by base angles therom, AC=9 ft

#12

m<M=m<N=m<P=60 <- Triangle is equilateral

#13

2(8x-23)+34=180 <- Sum of angles in triangle

16x-12=180

16x=192

x=12

#14

3(9x-3)=180 <- Su, of angles in triangle

9x-3=60

9x=63

x=7

#15

4x+9=16x-27 <- Legs of isosceles triangle

12x=36

x=3

Now substitute


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3 years ago
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