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SOVA2 [1]
3 years ago
13

How many non perfect squares are there in between 35square and 36square

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0
1 square sorry if I’m wrong
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A hotel manager's salary is $61,410, which is a 15% increase over the previous year's salary. What was the previous year's salar
irga5000 [103]

Answer:

52,198.5

Step-by-step explanation:

61,410 x .15

= 9211.5

61,410-9211.5 = 52,198.5

8 0
3 years ago
Sixty is 20 percent less than what number?​
emmainna [20.7K]

Answer:

75

Step-by-step explanation:

If it is 20% less, that means 60 is 80% of whatever the number is we are trying to find. Therefore, multiply 60 by 100/80.

60 x 100/80 = 75

8 0
4 years ago
how many gallons of a 70% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 60% antif
Law Incorporation [45]

Answer:m(.70)+80(.25)=.6(m+80)

.7m+20=.6m+48

.1m=28

m=28/.1=280 gallons of 25% antifreeze needed

Step-by-step explanation:

6 0
3 years ago
A rectangular plot of land measures 120 feet by 96 feet. Which dimensions could not represent the plot on a scale drawing?
Tresset [83]
The answer is b. if you divide 120 and 96, you would get 20 inches.
6 0
4 years ago
Read 2 more answers
Show all of your work, even though the question may not explicitly remind you to do so. Clearly label any functions, graphs, tab
natta225 [31]

Answer:

  (a) at t=2, the particle is moving toward the origin

  (b) a(t) = 70(8 -9t^2)/(3t^2 +8)^3; a(2) = -0.245

  (c) the particle approaches x = 1/3 as t gets large

Step-by-step explanation:

(a) The function x(t) is negative for -3 < t < 3, so at t = 2, the particle is to the left of the origin.

The velocity of the particle is given by the derivative of the position function:

  x'(t)=\dfrac{(3t^2+8)(2t)-(t^2-9)(6t)}{(3t^2+8)^2}=\dfrac{70t}{(3t^2+8)^2}

Then, at t=2, the expression is positive, indicating the particle is moving toward the origin.

__

(b) The acceleration is the derivative of the velocity, so is ...

  a(t)=\dfrac{70(3t^2+8)^2-(70t)(12t)(3t^2+8)}{(3t^2+8)^4}=\dfrac{70(3t^2+8-12t^2)}{(3t^2+8)^3}\\\\\boxed{a(t)=\dfrac{70(8-9t^2)}{(3t^2+8)^3}}

Then at t=2, the acceleration is ...

  a(2) = 70(8 -9·4)/(3·4+8)^3 = 70(-28)/8000

  a(2) = -0.245

__

(c) As t gets large, the value of x(t) approaches t^2/(3t^2) = 1/3.

7 0
4 years ago
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