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3 years ago

How can you graph m(x)=5x and then compare it to f(x)=x?

1 answer:

5 0

Graph the line y=5x. Then graph the line y=x. Then look at them and describe in what ways they are the same or different.

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Simplify the following expression <br> (X9 Y5) -4

KATRIN_1 [288]

Answer:

Step-by-step explanation:

$( x^{9} y^{5} )^{-4} \\x^{(9)(-4)} y^{(5)(-4)} \\x^{-36}y^{-20} \\\frac{1}{x^{36}y^{20}}$

3 0

2 years ago

Read 2 more answers

What would you have to do to make the line y = 2x -7 steeper on the coordinate plane?

ValentinkaMS [17]

The slope, if increased, would make the line y=2x-7 steeper. If you were to increase the y intercept, you would just move the line, not tilt it. Suggest changing it to 4x-7 = y or 8x-7= y, if you increase the slope, it'll make it steeper.

6 0

3 years ago

-3(ñ-4)+15=-5(ñ-7)-10

Mumz [18]

Answer:

ñ = -1

Step-by-step explanation:

7 0

3 years ago

A pan is heated to 393°F, then removed from the heat and allowed to cool in a kitchen where the room temperature is a constant 6

deff fn [24]

Answer:

The approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

Step-by-step explanation:

The formula for D, the difference in temperature between the pan and the room after t minutes is:

$D = 324\cdot e^{-0.05t}$

Compute the approximate difference in temperature between the pan and the room after 9 minutes as follows:

$D = 324\cdot e^{-0.05t}$

$=324\times e^{-0.05\times 9}\\\\=206.59$

Then the approximate temperature of the pan after it has been away from the heat for 9 minutes is:

D = P - R

206.59 = P - 69

P = 206.59 + 69

P = 275.59°F

Thus, the approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

6 0

2 years ago

Help pleas eldkjsdweggrwsddwsf

Cloud [144]

I agree with the top guy

7 0

2 years ago