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lana [24]
3 years ago
12

Please help me solve this thank you so much.

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0
Y= -3. Someone else had the same question I just answered lol
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Equation of the line passing through (7,5) and (1, 2)​
Trava [24]

Answer:

y = \frac{1}{2}x + \frac{3}{2}

Step-by-step explanation:

Assuming this is a linear equation in the form of y = mx + b, we can first solve for the slope using \frac{y_2 - y_1}{x_2 - x_1}, for these points, the slope would be \frac{1}{2}. Now we plug in the points to get the equation:

plugging in (7,5), we get 5 = \frac{1}{2} ×7 + b

and solving for b, we get b = \frac{3}{2}

therefore, the equation of the line passing through (7,5) and (1,2) is y = \frac{1}{2}x + \frac{3}{2}.

hope this helps!

6 0
2 years ago
Please solve the following right triangle below. The round the following decimal answers to the nearest tenth.
alekssr [168]

K=180^{\circ}-90^{\circ}-40^{\circ}=50^{\circ}.

KL=\sin(40^{\circ})\cdot8\approx5.1.

ML=\cos(40^{\circ})\cdot8\approx6.1.

Hope this helps.

8 0
3 years ago
Question #2<br> What is the value of the expression<br> 35<br> ?<br> 23 – 1<br> A 5<br> B 7<br> C 12
algol13

Answer:

A. 5

Step-by-step explanation:

just use calculator tbh

6 0
3 years ago
Read 2 more answers
NO SILLY ANSWERS PLEASE <br> Can someone help me with this?
marusya05 [52]
Keep in mind that, when the logarithm base is not explicitly written, base 10 is assumed, therefore,

\bf \textit{Logarithm Cancellation Rules}\\\\&#10;log_a a^x\implies x\qquad \qquad a^{log_ax}=x\\\\&#10;-------------------------------\\\\&#10;10^{log(3)}+log(100)\implies 10^{log_{10}(3)}+log_{10}(100)\implies 3+log_{10}(10^2)&#10;\\\\\\&#10;3+2\implies 5
7 0
4 years ago
Destin walked 2km and Jane walked 4,000 ft. What is the approximate combined distance they walked? Note: 1 Foot (ft) is equal to
Anna11 [10]

Answer: Option C.

Step-by-step explanation:

The data is:

Destin walked 2km

Jane walked 4000ft.

Let's write both of those in the same units.

The data given is:

1ft = 0.0003048km.

and 4000ft is 4000 times that:

4000ft = 4000*1ft = 4000*0.0003048km = 1.22km

Then if we add those, we get:

Total distance = 2km + 1.22km = 3.22km

So we can already discard option D.

Now, we know that:

1km = 0.6214 miles.

then 3.22 km is 3.22 times that amount:

3.22km = 3.22*1km = 3.22*(0.6214 mi) = 2 miles

The correct option is C.

3 0
3 years ago
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