All categories

3 years ago

Question 1

Mathematics

1 answer:

inessss [21]3 years ago

4 0

Answer:

Least possible value of b is 9.

Step-by-step explanation:

It is given that $7b-8>4b+16$ and b is an odd integer.

We need to find the least possible value of b.

We have,

$7b-8>4b+16$

Isolate variable terms.

$7b-4b>8+16$

$3b>24$

Divide both sides by 3.

$b>8$

Since b>8 and b an odd integer, therefore the possible values of b are 9, 11, 13, 15, ... .

Hence, the least possible value of b is 9.

You might be interested in

Can you help me with this question?

Masteriza [31]

Answer:

Step-by-step explanation:

1. A + B

2. 9 + u - 10

3. m - 2 / 2

3 0

3 years ago

What are the solutions of the following equation?

noname [10]

Answer:

D. x = 7 and x = 14

Step-by-step explanation:

this is a quadratic equation, so use the quadratic formula: (-b+-√b^2-4ac) / 2a for ax^2+bx+c=0

7 0

3 years ago

5^x + 5^x+1= 150 Find x Help me pls i need soon Tksss

raketka [301]

Answer:

$x=2$

Step-by-step explanation:

So we have the equation:

$5^x+5^{x+1}=150$

First, separate the second term:

$5^x+(5\cdot5^x)=150$

Let u equal 5ˣ. So:

$u+5u=150$

Combine like terms:

$6u=150$

Divide both sides by 6:

$u=25$

Substitute back u:

$5^x=25$

Take the base 5 logarithm of both sides:

$\log_5(5^x)=\log_5(25)$

The left cancels:

$x=\log_5(25)$

Evaluate the right:

$x=2$

So, our answer is 2.

And we're done!

5 0

3 years ago

What is this number written in standard form 3×1,000,00+3×100,00+2×100

pav-90 [236]

3(1,000,000)=3,000,000
3(100,000)=300,000
2(100)=200
3,300,200

6 0

3 years ago

Read 2 more answers

A rectangular poster is 3 times as long as it is wide. A rectangular banner is 5 times as it is wide. Both the banner and the po

Svetradugi [14.3K]

The length and width of poster are 9 inches and 3 inches respectively and length and width of banner are 10 inches and 2 inches respectively

Solution:

Given, A rectangular poster is 3 times as long as it is wide.

Rectangular banner is 5 times as long as it is wide.

Both the banner and the poster have perimeters of 24 inches

Let, the width of poster be p, then its length will be 3p

And, the width of banner be b, then its length will be 5b

Now, according to given information,

Perimeter of poster = 24 inches and perimeter of banner = 24 inches

2(length of poster + width of poster) = 24

2(3p + p) = 24

2(4p) = 24

8p = 24

p = 3

And 2(length of banner + width of banner) = 24

2(5b + b) = 24

2(6b) = 24

12b = 24

b = 2

So, width of poster is 3 inches, then length of poster is 3p = 3 x 3 = 9 inches

And, width of banner is 2 inches, then length of banner is 5b = 5 x 2 = 10 inches

8 0

3 years ago