Answer:
![(\frac{3^{-1}+2^{-1}}{5^{-1}})^{-1}+3=\frac{81}{25}](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%5E%7B-1%7D%2B2%5E%7B-1%7D%7D%7B5%5E%7B-1%7D%7D%29%5E%7B-1%7D%2B3%3D%5Cfrac%7B81%7D%7B25%7D)
Step-by-step explanation:
Given expression is,
![(\frac{3^{-1}+2^{-1}}{5^{-1}})^{-1}+3](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%5E%7B-1%7D%2B2%5E%7B-1%7D%7D%7B5%5E%7B-1%7D%7D%29%5E%7B-1%7D%2B3)
By solving the given expression,
![(\frac{3^{-1}+2^{-1}}{5^{-1}})^{-1}+3=(\frac{\frac{1}{3}+\frac{1}{2}}{\frac{1}{5}})^{-1}+3](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%5E%7B-1%7D%2B2%5E%7B-1%7D%7D%7B5%5E%7B-1%7D%7D%29%5E%7B-1%7D%2B3%3D%28%5Cfrac%7B%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B2%7D%7D%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5E%7B-1%7D%2B3)
![=(\frac{\frac{2+3}{6}}{\frac{1}{5}})^{-1}+3](https://tex.z-dn.net/?f=%3D%28%5Cfrac%7B%5Cfrac%7B2%2B3%7D%7B6%7D%7D%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5E%7B-1%7D%2B3)
![=(\frac{\frac{5}{6}}{\frac{1}{5}})^{-1}+3](https://tex.z-dn.net/?f=%3D%28%5Cfrac%7B%5Cfrac%7B5%7D%7B6%7D%7D%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5E%7B-1%7D%2B3)
![=(\frac{5}{6}\times \frac{5}{1})^{-1}+3](https://tex.z-dn.net/?f=%3D%28%5Cfrac%7B5%7D%7B6%7D%5Ctimes%20%5Cfrac%7B5%7D%7B1%7D%29%5E%7B-1%7D%2B3)
![=(\frac{25}{6})^{-1}+3](https://tex.z-dn.net/?f=%3D%28%5Cfrac%7B25%7D%7B6%7D%29%5E%7B-1%7D%2B3)
![=\frac{6}{25}+3](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6%7D%7B25%7D%2B3)
![=\frac{6+(25\times 3)}{25}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6%2B%2825%5Ctimes%203%29%7D%7B25%7D)
![=\frac{81}{25}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B81%7D%7B25%7D)
It a negative slope. Start at 1 and then go down 3 and left 7 :)
APY=(1+0.045÷4)^(4)−1
=0.0458×100=4.58%
Answer:
4x⁴-3x⁴+5x³-3x²+1
Step-by-step explanation:
Given that p (x) = 3x^3+2x^2+4x^4+3 and q (x) = 3x^4-2-x+5x^2
p (x) - q (x) = 3x^3+2x^2+4x^4+3 - (3x^4-2-x+5x^2)
p (x) - q (x) = 3x^3+2x^2+4x^4+3 - 3x^4 + 2 + x - 5x^2
Collect the like terms
p (x) - q (x) = 4x⁴-3x⁴+3x³+2x²-5x²+x+3-2
p (x) - q (x) = 4x⁴-3x⁴+5x³-3x²+1
This givess the difference
Complete question :
Kane is training for a marathon. He starts by running 3 miles during every training session each week plans to increase the distance of his runs by 1/4 mile. Let w be the number of weeks. Write and expression to show the diatance kane runs in a training session after w weeks
Answer:
(11 + w ) / 4
Step-by-step explanation:
Given the following :
Initial miles kane plans to cover per session = 3 miles
Increase in miles covered per session = 1/4 mile per week
Hence, distance covered after w weeks :
Using the sum of an arithmetic progression formula:
Tn = a + (n - 1) d
a = first term = Initial / starting distance = 3 miles
n = nth term = number of weeks = w
d = common difference = constant increase in distance per week = 1/4
Hence, after w weeks :
= 3 + (w - 1) × 1/4
= 3 + (w/4 - 1/4)
= 3 + (w - 1) / 4
Taking L. C. M
(12 + w - 1) / 4
(11 + w ) / 4