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2 years ago

5(x-3) = 2(x+3) solve for x

Mathematics

2 answers:

sattari [20]2 years ago

4 0

Answer:

Step-by-step explanation:

5(x - 3) = 2(x + 3) Distribute

5x - 15 = 2x + 6

+ 15 + 15 Switch sides to the liked terms

5x = 2x + 6 + 15

-2x -2x Switch sides to the liked terms

5x - 2x = 6 + 15

3x = 21 Divide

3 3

x = 7

skelet666 [1.2K]2 years ago

3 0

Answer:

x = 7

Step-by-step explanation:

Equation: 5(x-3) = 2(x+3)

Step 1: Simplify the equation.

5 (x − 3) = 2(x + 3)

(5)(x) + (5)(−3) = (2)(x) + (2)(3) Distribute

5x + −15 = 2x + 6

5x − 15 = 2x + 6

Step 2: Subtract 2x.

5x − 15 −2x = 2x + 6 −2x

3x − 15 = 6

Step 3: Add 15.

3x − 15 + 15 = 6 + 15

3x = 21

Step 4: Divide by 3.

$\frac{3x}{3} = \frac{21}{3}$

Step 5: Divide 21 by 3.

The answer is x = 7.

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3 years ago

Find the length of the third side. If necessary, write in simplest radical form.

Mazyrski [523]

Answer:

$\boxed {\boxed {\sf 8}}$

Step-by-step explanation:

This triangle has a small square, which represents a right angle. Therefore, we can use the Pythagorean Theorem.

$a^2+b^2=c^2$

Where a and b are the legs of the triangle and c is the hypotenuse.

In this triangle, 7 and √15 are the legs, because these sides make up the right angle. The unknown side is the hypotenuse, because it is opposite the right angle. So, we know two values:

$a= 7 \\b= \sqrt{15}$

Substitute these values into the formula.

$(7)^2+(\sqrt{15})^2=c^2$

Solve the exponents.

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$49+15=c^2$

Add.

$64=c^2$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt{64}=\sqrt{c^2} \\\sqrt{64}= c\\8=c$