Find the complete solution in the given attachments.
Note: The complete Question is attached in the first attachment as the provided question was incomplete
Answer:
The governing ratio for thin walled cylinders is 10 if you use the radius. So if you divide the cylinder´s radius by its thickness and your result is more than 10, then you can use the thin walled cylinder stress formulas, in other words:
- if
then you have a thin walled cylinder
or using the diameter:
- if
then you have a thin walled cylinder
Answer:
The total design can be summarized as follows:
AC motor 55 hp, 750 rpm as a driver
Service factor 1.0
Design power 5 hp
No. 40 chain, 0.50 in pitch, 1 strands
17 teeth, 2.72 in pitch dia, 1 strand small sprocket
39 teeth, 7.46 in pitch dia, 1 strand large sprocket
1 strand of length 54 in
Center distance of 19.9 in
Actual Output speed of 326.9 rpm
Type B lubrication
Explanation:
Answer:
Percent Elongation = 52.72%
Percent Reduction in Area = 64%
Explanation:
First we find percent elongation:
Percent Elongation = {Final Gage Length - Initial Gauge Length/Initial Guage Length} x 100%
Percent Elongation = {(4.20 in - 2.75 in)/2.75 in} x 100%
<u>Percent Elongation = 52.72%</u>
Now, for the percent reduction in area:
Percent Reduction in Area = {Final Cross Sectional Area - Initial Cross Sectional Area|/Initial Cross Sectional Area Length} x 100%
Percent Reduction in Area = {π(0.3 in)² - π(0.5 in)²/π(0.5 in)²} x 100%
<u>Percent Reduction in Area = - 64%</u>
here, negative sign shows a decrease in area.
Answer:
to prevent asbestos fibers poisoning
Explanation:
There is a potential for asbestos fibers to be released when removing asbestos-containing material,using personal protective equipment will significantly reduce your exposure to asbestos fibers.