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vekshin1
3 years ago
13

How do you write a an equation to represent a real world situation

Mathematics
1 answer:
Sauron [17]3 years ago
8 0
Well, there's many equations that represent real world situations. These equations we use a lot in engineering. For example, something fundamental is that we can calculate the velocity of something by knowing it's acceleration by taking the integral of the acceleration.
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Define fn : [0,1] --> R by the
sasho [114]

Answer:

The sequence of functions \{x^{n}\}_{n\in \mathbb{N}} converges to the function

f(x)=\begin{cases}0&0\leq x.

Step-by-step explanation:

The limit \lim_{n\to \infty }c^{n} exists and converges to zero whenever \lvert c \rvert. But, if c=1 the sequence \{c^{n}\} is constant and all its terms are equal to 1, then converges to 1. Using this result, consider the sequence of functions \{f_{n}\} defined on the interval [0,1] by f_{n}(x)=x^{n}. Then, for all 0\leq x we have that \lim_{n\to \infty}x^{n}=0. Now, if x=1, then \lim_{n\to \infty }x^{n}=1. Therefore, the limit function of the sequence of functions is

f(x)=\begin{cases}0&0\leq x.

To show that the convergence is not uniform consider 0. For any n>1 choose x\in (0,1)  such that \varepsilon^{1/n}. Then

\varepsilon

This implies that the convergence is not uniform.

8 0
3 years ago
ABC ~ DEF and the scale factor from ABC to DEF is 1/2, what are the lengths of DE
Likurg_2 [28]

Answer:

13

Step-by-step explanation:

ABC ~ DEF means that ABC and DEF are the same triangle either expanded or contracted.

In this case the scale factor is 1/2. That means DEF is half ABC.

Since AB = 26 then DE must be 26/2 = 13

6 0
3 years ago
Can anyone help me with this fraction <br> x/-4 = 9 =
olasank [31]

Answer:  x= -36

Step-by-step explanation:

-36/-4=9

5 0
3 years ago
Find the exact value of sin(7pi/8)
suter [353]

Answer:2.74889357189

Step-by-step explanation:

3 0
2 years ago
Question 1 of 40<br> If f(x) = 4x² - 6 and g(x) = x² - 4x-8, find (f- g)(x).
Aleksandr-060686 [28]

Answer:

\huge\boxed{\sf (f-g)(x) = 3x\² + 4x - 14}

Step-by-step explanation:

<h3><u>Given functions:</u></h3>
  • f(x) = 4x² - 6
  • g(x) = x² - 4x - 8
<h3><u>Solution:</u></h3>

Subtract both functions

(f-g)(x) = 4x² - 6 - (x² - 4x - 8)

(f-g)(x) = 4x² - 6 - x² + 4x - 8

Combine like terms

(f-g)(x) = 4x² - x² + 4x - 6 - 8

(f-g)(x) = 3x² + 4x - 14

\rule[225]{225}{2}

3 0
2 years ago
Read 2 more answers
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