The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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You spent 40% of your budget.
10/25=2/5=40/100
Answer:
____________
the answer is B
___________
explanation
Factor out the greatest common factor from each group.
Group the first two terms and the last two terms.
(x^2 - 2x) - 3xy + 6y
Factor out the greatest common factor (GCF) from each group.
x(x - 2) - 3y (x - 2)
Factor the polynomial by factoring out the greatest common factor, x - 2
(x - 2) (x - 3y)
Answer:
The answer to your question is Yes.
Step-by-step explanation:
The math in this problem is that we need to use the Pythagorean theorem to solve it. Pythagorean theorem is part of trigonometry a branch of Maths.
Data
base = 9 ft
length = 37 ft
height = ?
Pythagorean theorem
c² = a² + b²
length = c
base = a
height = b
37² = 9² + b²
-Solve for b
b² = 37² - 9²
-Simplify
b² = 1369 - 81
b² = 1288
-Result
b = 35.88
-Conclusion
The ladder will reach a height higher than 35 ft.
Answer:
b. (-1, 5)
Step-by-step explanation:
Since the first equation is already solved for y, we can use substitution.
Substitute y in the second equation with 3x + 8.
5x + 2y = 5
5x + 2(3x + 8) = 5
5x + 6x + 16 = 5
11x = -11
x = -11/11
x = -1
Now substitute x in the first original equation by -1 and solve for y.
y = 3x + 8
y = 3(-1) + 8
y = -3 + 8
y = 5
Answer: (-1, 5)