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valentinak56 [21]
3 years ago
5

Alexus deposited $1900 into a savings account that pays a simple annual interest rate of 1.8%. how much interest will she earn a

fter 9 months?
Mathematics
2 answers:
elena55 [62]3 years ago
4 0
1900 x 0.018 x 0.75 = 25.65


1900(0.018) = $34.20 for 1 year.

(9/12)(34.20) = $25.65 for 9 months.

Answer: $25.65
g100num [7]3 years ago
4 0

Answer:

$25.65

Step-by-step explanation:

We have been given that Alexus deposited $1900 into a savings account that pays a simple annual interest rate of 1.8%.

To find the amount of interest earned in 9 months we will use simple interest formula.

I=Prt, where,

I=\text{Amount of interest},

P=\text{Principal amount},

r=\text{Interest rate in decimal form},

t=\text{Time in years}

Let us convert our given interest rate in decimal form and time in years.

1.8\%=\frac{1.8}{100}=0.018

9\text{ months}=\frac{9}{12}\text{ year}=\frac{3}{4}\text{ year}=0.75\text{ year}

Upon substituting our given values in simple interest formula we will get,

I=\$1900*0.018*0.75

I=\$25.65

Therefore, Alexus will earn an amount of $25.65 in interest after 9 months.

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The measure of ∠P to the nearest 10th of a degree is 84.8°

<h3>Law of Cosines </h3>

From the question, we are to determine the measure of ∠P

From the law of cosines, we can write that

cos \ P=\frac{o^{2}+q^{2}-p^{2} }{2oq}

From the given information,

o = 500 cm

p = 600 cm

q = 380 cm

Putting the parameters into the formula, we get

cos \ P=\frac{500^{2}+380^{2}-600^{2} }{2\times 500 \times 380}

cos \ P =\frac{34400}{380000}

cos \ P =0.0905

P = cos⁻¹(0.0905)

P = 84.8076

P ≅ 84.8°

Hence, the measure of ∠P to the nearest 10th of a degree is 84.8°

Learn more on the Law of Cosines here: brainly.com/question/20890746

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Would it make sense to use this model to predict the age difference between​ husband/wife in a country where the literacy rate i
pychu [463]

Answer:

The question is incomplete because it was unable to give direction on what action to take. However, kindly find the complete question below.

Question:

Is there a relation between the age difference between husband/wives and the percent of a country that is literate. Researchers found the least -squares regression between age difference (husband age minus wife age),y, and literacy rate (percent of the population that is literate), x, is y^=−0.0527x+7.1. The model applied for 18≤x≤100. (a) Interpret the slope. (b) Does it make sense to interpret they-intercept? Explain. (c) Predict the age difference between husband/wife in a country where the literacy rate is 25 percent. (d) Would it make sense to use this model to predict the age difference between husband/wife in a country where the literacy rate is 10 percent? Explain. (e) The literacy rate in the United States is 99 percent and the age difference between husbands and wives is 2 years. Is this age difference above or below the average age difference among all countries whose literacy rate is 99 percent?

Step-by-step explanation:

Given the model

          : y^ = − 0 . 0527x + 7.1

(a) The slope represents the average increase (decrease) in y per unit of x.

The age difference between husband and wife decreases by 0.0527 years per percentage (%) of literacy rate.

(b) It does not make sense to interpret the y intercept, because the literacy rate of 0 % is not in the given range of literacy rates ( 18 ≤ x ≤ 100 ) and the pattern between the variables could change outside of the given range of x - axis.

(c) Replace x in the given equation by 25 and evaluate:

we then have: y^ = − 0 . 0527 (25)  + 7.1 = 5.7825

Thus, the predicted age difference is 5.7825 years.

(d) It does not make sense to make a prediction for 10% literacy rate because the literacy rate of 10% is not in the given range of literacy rates

( 18 ≤ x ≤ 100 ) and the pattern between the variables could change outside of the given range of x - values

(e) Replace x in the given equation by 99 and we calculate thus

y^ = − 0 . 0527 (99)  + 7.1 = 1.8827

Hence, the average age difference is 1.8827 years and 2 years is then above the average age difference.

So the answers are :

(a) The average difference between husband and wife decrease by 0.0527 years per % of literacy rate

(b) No

(c) 5.7825 years

(d) No

(e) Above

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ivolga24 [154]

Answer:

x=27.5

Step-by-step explanation:

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Cross multiply:

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Divide:

8x/8=220/8

x=27.5

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