Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The other parameters are given as follows:

Hence, the lower bound of the interval is:

The lower limit of the 95% confidence interval is of $99,002.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:

Step-by-step explanation:








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you can plug the x value (9y) into the second equation
5(9y) + 3y = -48
45y + 3y = -48
48y = -48
y = -1
x = 9(-1)
x = -9
There should be an X over 9.6, 0, √16, and 2.45.
9.6 = Integer
0 = Whole Number
√16 (or 4) = Counting Numbers
2.45 = Integer
Answer:
D
Step-by-step explanation:
given p² + 4p - 12 = 0 ← in standard form
with a = 1, b = 4, c = - 12, then the discriminant
Δ = b² - 4ac
= 4² - (4 × 1 × - 12) = 16 - (- 48) = 16 + 48 = 64 → D