Claim: The difference between two rational numbers always is a rational number
Proof: You have a/b - c/d with a,b,c,d being integers and b,d not equal to 0.
Then:
a/b - c/d ----> ad/bd - bc/bd -----> (ad - bc)/bd
Since ad, bc, and bd are integers since integers are closed under the operation of multiplication and ad-bc is an integer since integers are closed under the operation of subtraction, then (ad-bc)/bd is a rational number since it is in the form of 1 integer divided by another and the denominator is not eqaul to 0 since b and d were not equal to 0. Thus a/b - c/d is a rational number.
Answer:
None are equivalent
Step-by-step explanation:
Answer:
3(60/10)
Step-by-step explanation:
10 students require 3 cookies, which you already know. So, since you need to find for 60, you can divide 60 by 10 into 6. Then, 6x3 will equal 18. Or, you can say:
10=3
20=6
30=9
40=12
50=15
60=18
10x2=3x2 and so forth....
