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Andre45 [30]
3 years ago
8

Matt has

Mathematics
2 answers:
Vlad [161]3 years ago
5 0

Answer:

Fix the layout of the question because I cant tell the numbers

Step-by-step explanation:

Snowcat [4.5K]3 years ago
5 0
The answer is 2 7/10 boxes
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What is the quotient. Of 25)9250
saul85 [17]

Answer:

370

Step-by-step explanation:

Isolate the numbers so that you are only dividing sections at a time.

So 25 goes in to 92 three times. so we multiply 25 by three and subtract that from 92. Put the three at the top and repeat throughout.

92-75=17

Bring the next number down and repeat.

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3 years ago
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100 Points
kakasveta [241]

Answer:

Step-by-step explanation:

f(-x) is a reflection of f(x) in the y-axis

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This table shows information about two occupations.
ycow [4]

yes it can be possible to do

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3 years ago
Which property can be used to solve the equation?<br><br> 5 d = 75
timama [110]

Answer:

Division

Step-by-step explanation:

To isolate d and solve the equation, divide 75 by 5.

4 0
3 years ago
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Help pleaseeeeeeeeeeeeeeeeeeeeeee
bixtya [17]

Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

3 0
3 years ago
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