Find three consecutive integers such that the sum of the first and third is 22.
1 answer:
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Answer:
48+23(6)½
Step-by-step explanation:
A = l × w
A =[(8-(6)^½) × (9+4(6)^½)]
A =8(9+4(6)^½) + [-(6)^½(9+4(6)^½]
A =(72 + 32(6)^½ - 9(6)^½ - 24)
A =(72 - 24 + 32(6)^½ - 9(6)^½)
A =(48 + 23(6)^½)
